3 years ago

Need 24 26 28 and 30 dne, first correct will get brainiest

Mathematics

1 answer:

Galina-37 [17]3 years ago

3 0

Answer:

Many answers, look below :)

Step-by-step explanation:

24.

(x)=2x^5+6x^4

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Find the distance between the two points (2,5) and (6,-1)

Reptile [31]

Answer:

= $\sqrt{52}$ units

Step-by-step explanation:

x₁ = 2 ; y₁ = 5

x₂ = 6 ; y₂ = -1

D = $\sqrt{(x₂ - x₁)² + (y₂ - y₁)²}$

= $\sqrt{(6 - 2)² + (-1 -5)²}$

= $\sqrt{4² + (-6)²}$

= $\sqrt{16 + 36}$

D = $\sqrt{52}$ units

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Answer:

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Step-by-step explanation:

2/3 of 42 is 14 multiplied by ten is 140

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3 years ago

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Answer: y-5=1/3(x-0)

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3 years ago

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1 and 1/4..................................

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Find the distance between A and B.

Papessa [141]

Answer:

The result is $d = 2\sqrt{5}$ units.

Step-by-step explanation:

The coordinates for A and B:

A = (-2, 0)

B = (2, 2)

-To find the distance between A and B, you need the distance formula:

$d = \sqrt{(x_{2} - x_{1})^2 + (y_{2}-y_{1})^2}$ Where the first coordinate is $(x_{1},y_{1})$ and the second coordinate is $(x_{2}, y_{2})$ .

-Use the coordinates A and B for the equation:

$d = \sqrt{(2+2)^2 + (2-0)^2}$

-Then, you solve the equation:

$d = \sqrt{(2+2)^2 + (2-0)^2}$

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$d = \sqrt{16 + 4}$

$d = \sqrt{20}$

$d = 2\sqrt{5}$

So, therefore the distance is $2\sqrt{5}$ units.

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3 years ago