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LekaFEV [45]
2 years ago
5

A map of California has a scale factor of 1 inch = 16 miles. The distance on the map from Riverside to Chula Vista is 3.5 inches

. How far are the two cities in real life?
Mathematics
1 answer:
kvasek [131]2 years ago
7 0

Answer:

56 miles

Step-by-step explanation:

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For the graph, what is a reasonable constraint so that the function is at least 600?
Harman [31]

Answer:

I remember taking this too. So, the correct answer is A! I SWEAR ITS RIGHT!

Step-by-step explanation:

7 0
3 years ago
Lori needs at least 12 liters of water to fill a water cooler. She has a container with 4.55 liters of
Stels [109]

Answer:

<u></u>

  • <u>Yes, she has enough water.</u>

Explanation:

To <em>estimate</em> the value, you can work with friendly numbers: numbers closed to the given numbers and with which you can perform easy mental calculations.

For example 4.55 may be rouned to 5, 4.85 may be rounded to 5, and 3.25 may be rounded to 3. That yields 5 + 5 + 3 = 13

Then, it seems you have about 13 liters. Is the final number equal or greater than 12 for sure?

To round 4.55 to 5 you increased the amount in 0.45, to round 4.85 to 5 you increased the amount by 0.15, and to round 3.25 to 3 you decreased the amount in 0.25.

What was the net change in your values: 0.45 + 0.15 - 0.25 = 0.60 - 0.25 = 0.35. Those are easy calculations that you can perform in your mind.

That means that you increased your total in less than 1 liter. Meaning that the final total is overestimated by 0.35, and that if you used the real amounts to make the calculations, the total will be still more than 12.

4 0
3 years ago
The pier is 200 meters long. each board is 80 centimeters wide. how many boards are in the pier?
Artemon [7]
100 cm = 1 meter
80 cm = 0.8 meter
200 meters/.8 meters = number of boards
250
6 0
3 years ago
A=1/2 ap <br> What is the value of p if A=40ft2 and <br> a= 8ft?
cricket20 [7]
A=1/2ap

(40ft^2)=1/2*8*p

p=(40ft^2)/4
7 0
3 years ago
Evaluate the following double integral where a = 2y
Keith_Richards [23]

Change the order of integration.

\displaystyle \int_0^1 \int_{2y}^2 \cos(x^2) \, dx \, dy = \int_0^2 \int_0^{x/2} \cos(x^2) \, dy \, dx \\\\ ~~~~~~~~ = \int_0^2 \cos(x^2) y \bigg|_{y=0}^{y=x/2} \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^2 x \cos(x^2) \, dx

Substitute u=x^2 and du=2x\,dx.

\displaystyle \frac12 \int_0^2 x \cos(x^2) \, dx = \frac14 \int_0^4 \cos(u) \, du = \frac14 \sin(u) \bigg|_{u=0}^{u=4} = \boxed{\frac{\sin(4)}4}

4 0
1 year ago
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