Answer:
Hello! Benny is 25%of his Moms age
Step-by-step explanation:
Well first 9450/5=1890 then 1890/6= 315 watt hours per day
Answer:
420 m^2
Step-by-step explanation:
Ancho: x
Largo: 2x + 2
2x + 2(2x+2) = 88
2x + 4x + 4 = 88
6x = 88 - 4
x = 84/6
x = 14
Ancho: 14
Largo : 30
Area: 14 * 30 = 420 metros cuadrados
Answer:
(a). 72.9%.
(b). 13.6 hr.
Step-by-step explanation:
So, we are given the following data or parameters or information which is going to assist us in solving this question/problem;
=> "A welder produces 7 welded assemblies during the first day on a new job, and the seventh assembly takes 45 minutes (unit time). "
=> The worker produces 10 welded assemblies on the second day, and the 10th assembly on the second day takes 30 minutes"
So, we will be making use of the Crawford learning curve model.
T(7) + 10 = T (17) = 30 min.
T(7) = T1(7)^b = 45.
T(17 ) = T1(17)^b = 30.
(T1) = 45/7^b = 30/17^b.
45/30 = 7^b/17^b = (7/17)^b.
1.5 = (0.41177)^b.
ln 1.5 = b ln 0.41177.
0.40547 = -0.8873 b.
b = - 0.45696.
=> 2^ -0.45696 = 0.7285.
= 72.9%.
(b). T1= 45/7^ - 045696 = 109.5 hr.
V(TT)(17) = 109.5 {(17.51^ - 0.45696 – 0.51^ - 0.45696) / (1 - 0.45696)} .
V(TT) (17) = 109.5 {(4.7317 - 0.6863) / 0.54304} .
= 815.7 min .
= 13.595 hr.
AD || BC and BD is the transversal,
Therefore, angle DBC = angle ADB = 42° [alternate angles]
AD || BC and BD is the transversal,
angle BAD + angle ABD + angle DBC = 180° [co-interior angles]
or, 106°+ angle ABD + 42° = 180°
or, 148° + angle ABD = 180°
or, angle ABD = 180°-148° = 32°
Therefore, angle ABC = (32+42)° = 74°
AB||CD and BC is the transversal,
angle ABC + angle BCD = 180° [co-interior angles]
or, 72+2x+12 = 180
or, 84+2x = 180
or, 2x=180-84 = 96
or, x = 48
Answers: a)48°
b)42°
c)72°
