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Anon25 [30]
2 years ago
12

How do you solve 3/5 times 2/3

Mathematics
1 answer:
UkoKoshka [18]2 years ago
3 0
Hello! And thank you for your question!

First use the rule: A/b x c/d = ac/bd

3 x 2 over 5 x 3

Simplify 3 x 2:

6 over 5 x 3

Simplify 5 x 3:

6/15

Simplify further:

2/5

Final Answer:

2/5
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((((this is multiple choice and i raised the points but you have to pick two))))
nasty-shy [4]

f(x) = 2^(4x)

g(x) = 2^x

(fg) = 2^4x * 2^x = 2^5x

NOTE: When multiplying two powers with same base exponents add.

(f/g)(x) = (2^4x)/(2^x) = 2^3x

NOTE: And when dividing they subtract.

Answer: a and c

//Hope it helps.

3 0
2 years ago
!!!!!!!!!!!!!51 POINTS!!!!!!!! MULTIPLE CHOICE!!!!!!!!!!! PLEASE HELP!!!!!!!!!!!!!!!
Alex777 [14]
First do 4.04 mil - 3.66 mil to get .38 mil (which is 380 thousand) then divide 380,000/10 to get answer J. 38,000. Hope this helped
3 0
3 years ago
How do you do this please help
Nataly_w [17]
You have to multiple and divide
3 0
3 years ago
In a certain neighborhood, there's a sagging power line between two utility poles. The utility poles are 50 feet tall and 120 fe
e-lub [12.9K]
<h3>Answer:  33.75 feet</h3>

In fraction form, this value is equal to 135/4

33.75 ft is equivalent to 33 ft, 9 inches.

===============================================

Explanation:

Refer to the diagram below.

The key point to start with is point H, which is the vertex of the parabola.

Recall that vertex form is

y = a(x-h)^2 + k

What we'll do is plug in the vertex (h,k) = (60,30) which is the location of point H. We'll also plug in (0,45) which is the y intercept, aka the location of point C.

So,

y = a(x-h)^2 + k

y = a(x-60)^2 + 30 .... plug in vertex

45 = a(0-60)^2 + 30 .... plug in y intercept coordinates

45 = a(-60)^2 + 30

45 = a(3600) + 30

45 = 3600a + 30

45-30 = 3600a

3600a = 15

a = 15/3600

a = 1/240

This then means:

y = a(x-h)^2 + k

y = (1/240)(x-60)^2 + 30

This is the equation of our parabola. Plug in x = 30 to determine the height of point K

y = (1/240)(x-60)^2 + 30

y = (1/240)(30-60)^2 + 30

y = (1/240)(-30)^2 + 30

y = (1/240)(900) + 30

y = 15/4 + 30

y = 15/4 + 120/4

y = 135/4

y = 33.75

Therefore, the height of the power line, when it is 30 feet away from one of the poles, is 33.75 feet. This is the y coordinate of point K.

Side note: 33.75 ft = 33 ft + 0.75 ft = 33 ft + 12*0.75 in = 33 ft + 9 inches

8 0
2 years ago
Helpppppppppppppp my cousins work
SIZIF [17.4K]
•20x200
•4x1000
•8x500
•10x400
•16x250
•2x2000

any of those
7 0
3 years ago
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