Question

2) Consider the quadratic sequence 72, 100, 120, 132

Answer 1

Answer:

Tn = -4n²+40n+36

Step-by-step explanation:

A general quadratic sequence, Tn = an²+bn+c, where n is the term of the sequence.

So, when n = 1, Tn = 72, which means T1 = a+b+c=72.

when n = 2, Tn = 100, which means T2= 4a+2b+c = 100

when n = 3, Tn = 132, which means T3 = 9a+3b+c = 132.

Now, use a calcaulatot to solve the 3 variable simultaneous equation. According to my calculator, a = -4, b = 40, c = 36.

Hence, you a, b, and c in the Tn equation given above.

Therefore, Tn = -4n²+40n+36