56 points given to the team
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player =
The probability that athlete is a basketball player =
The probability that athlete is both basket ball player and football player =
We have to find the probability that an athlete chosen is either a football player or a basketball player .
Now we know that;
Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
Recall the angle sum identities:
Now,
Divide through numerator and denominator by to get
Next, we use the fact that lie in the first quadrant to determine that
So we then have
Finally,
The answer is 20 ,80-60=20
Answer:
C, 2.15
Step-by-step explanation:
Arabian Plate: 1.29x10^-4 = .000129
African Plate: 6x10^-5 = .000006
Once you've converted both into standard form, divide them to find the difference.
.000129/.000006 = 2.15