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CaHeK987 [17]
4 years ago
13

Lengths

Mathematics
1 answer:
Leto [7]4 years ago
7 0

Answer:

9.5 14.5 and 4.5

Step-by-step explanation:

That’s correct

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HELP ASAP!!! WILL MARK BRAINLIEST!!!
scoundrel [369]

your answer is B the second one!

8 0
4 years ago
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1. Which value of x satisfies the equation below?
seropon [69]
It’s A I think not sure
3 0
3 years ago
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Alexa has some dimes and some quarters. She has a minimum of 28 coins worth a maximum of $5.05 combined. If Alexa has 17 quarter
Lerok [7]

Answer:

There are no possible solutions

Step-by-step explanation:

Given:

Minimum number of coins Alexa has =28 coins

Number of quarters Alexa has = 17 quarters

Total amount in coins = $5.05 = 505 cents

Let number of dimes be = x coins

So we can have two inequalities.

1) Total number of coins

x+17\geq28\\  [Since minimum number of coins=28]

2) Total value of coins

10x+(25)(17)\leq505 [As 1 dime=10 cents and 1 quarter=25 cents]

10x+425\leq505

Solving inequality (1)

Subtracting both sides by 17.

x+17-17\geq28-17

∴ x\geq 11

Solving inequality (2)

Subtracting both sides by 425.

10x+425-425\leq505-425

10x\leq 80

Dividing both sides by 10.

\frac{10x}{10}\leq \frac{80}{10}

∴ x\leq 8

On combining both solutions

x\geq 11 and  x\leq 8 ,

we see that there are no possible solutions as number of dimes cannot be ≥11 and ≤8 at the same time.

7 0
3 years ago
Identify the hypothesis and conclusion of each conditional statement. Then write each sentence in if-then form
lukranit [14]

Answer:

If you place two collinear points, then they will fall on the same line

Step-by-step explanation:

?

3 0
3 years ago
Find all solutions to the equation. (1 point) sin x = square root of three divided by two.
Serggg [28]

Answer:

x=pi/3 + 2pi*k

x=2pi/3+2pi*k

Step-by-step explanation:

sin(x)=sqrt(3)/2

This happens twice in the first rotation on our unit circle.

It happens in the first quadrant and in the second quadrant. Third and fourth quadrants are negative for sine.

So we are looking for when the y-coordinate on the unit circle is sqrt(3)/2.

This is at pi/3 and 2pi/3.

So we can get all the solutions by adding +2pi*k to both of those.  This gives us a full rotation about the circle any number of k times. k is an integer.

So the solutions are

x=pi/3 + 2pi*k

x=2pi/3+2pi*k

4 0
3 years ago
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