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maw [93]
2 years ago
10

Wow 25 points and brainliest if you give a actual answer

Mathematics
2 answers:
Kruka [31]2 years ago
4 0

Answer:

2 to 4

3 to 6

5 to 10

7 to 14

Step-by-step explanation:

sorry if wrong

iragen [17]2 years ago
3 0

Answer:

2, 16, 14 in orders from top.

Step-by-step explanation:

a/4=1/2   4 x 0.5 = 2

3/b=1/2   3 x 2 = 6

5/10=1/2

7/c=1/2    7 x 2  = 14

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Help please! I will mark Brainiest!!
aleksklad [387]

Answer:

It is equal to each other

Step-by-step explanation:

\sqrt{\frac{1}{x^2}} = \frac{1}{x}\\\sqrt[3]{\frac{1}{x^3}} = \frac{1}{x}

6 0
2 years ago
PLEASE HELP ME WITH THIS QUESTION!!!!!
prohojiy [21]

Answer:

we have, 1953125=5⁹, so it cannot be a perfect square. If the last digit of a given number is 5, then the last three digits must be perfect squares, 025 or 225 or 625. Otherwise, that number cannot be a perfect square. And as 125 is not a perfect square, so no number ending with 125 can be a perfect square

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The circular stream of water from a faucet is observed to taper from a diameter of 20 mm to 10 mm in a distance of 50 cm. Determ
steposvetlana [31]

Solution:

From Bernoulli equation

\frac{1}{2}ρV_{1}^{2} + ρgh = \frac{1}{2}ρV_{2}^{2} , where ρ is density of water, h – height difference and V_{1} and V_{2}  are the velocities in upper and lower cross sections correspondingly. We take into account that the pressure in both cross-sections is the same and equal to the atmospheric one.

From the continuity and assuming water incompressible:

\pi r_{1}^{2}V_{1} = \pi r_{2}^{2}V_{2} , where A_{1} and A_{2} are the corresponding cross-sections. As the lower diameter is twice as low as the upper one, we can conclude that V_{1} = \frac{V_{2}}{4}

Inserting it back into Bernoulli equations produces:

V_{1} = \sqrt{\frac{2}{15}gh} = 0.26m/s and the flow rate is

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S_A_V [24]

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Step-by-step explanation:

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Semenov [28]

Answer:

4\sqrt{2} =5.66

Step-by-step explanation:

The square is in the circle, so the diameter is the diagonal line of the square. This divides the square into two right triangles.

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Substitute 8 in for x.

8\sqrt{2} is the diameter, so we divide in half to get the radius = 4\sqrt{2}

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