Answer:
It is equal to each other
Step-by-step explanation:
![\sqrt{\frac{1}{x^2}} = \frac{1}{x}\\\sqrt[3]{\frac{1}{x^3}} = \frac{1}{x}](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B1%7D%7Bx%5E2%7D%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D%5C%5C%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7Bx%5E3%7D%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D)
Answer:
we have, 1953125=5⁹, so it cannot be a perfect square. If the last digit of a given number is 5, then the last three digits must be perfect squares, 025 or 225 or 625. Otherwise, that number cannot be a perfect square. And as 125 is not a perfect square, so no number ending with 125 can be a perfect square
Answer:
189.875
Step-by-step explanation:
Answer:

Step-by-step explanation:
The square is in the circle, so the diameter is the diagonal line of the square. This divides the square into two right triangles.
Two sides of the right triangle equal 8. This qualifies it as a special right triangle. This triangle has two sides that = x (in this case 8) and the hypotenuse is
.
Substitute 8 in for x.
is the diameter, so we divide in half to get the radius = 