Question

Mis Meyer's paid $3600 all together for the equipment, furniture and decorations for her restaurant. The equipment cost $500 more than the furniture the furniture was twice as much as the decorations. How much did the equipment cost

Answer 1

Answer:

The equipment will cost $1740.

Step-by-step explanation:

Let the Cost of equipment, furniture and decoration be x, y and z.

Now, According to question,

x + y + z = 3600 ...... (1)  (cost of all items)

x = 500 + y (∵ equipment cost 500 more than furniture)

and y = 2z ( ∵ furniture twice as much as decoration)

so, z = y/2

Now substituting the value of x and z in eq (1)

$x + y + z = 3600$

$500 + y + y + \frac{y}{2} = 3600$

$2y + \frac{y}{2} = 3600 - 500$

$\frac{5y}{2} = 3100$

$y = \frac{3100\times 2}{5} = 1240$

So, the cost of furniture (y) = 1240

∴ Cost of equipment = y + 500 = 1240 + 500 = 1740

Therefore the cost of equipment was $1740.