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Nonamiya [84]
3 years ago
7

A sequence is defined by the recursive function f(n+1)=f(n)-2 If f(1)=10 what is f(3)?

Mathematics
2 answers:
Novosadov [1.4K]3 years ago
4 0

<u>Given </u><u>:</u><u>-</u><u> </u>

  • A sequence is defined by f(n + 1) = f(n) -2 .
  • f(1) = 10

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u><u> </u>

  • The value of f(3) .

<u>Sol</u><u>u</u><u>tion </u><u>:</u><u>-</u><u> </u>

As per Question ,

→ f(n + 1) = f(n) - 2

→ f(n + 1 ) - f(n ) = -2

Therefore , the second term of the sequence is ,

→ f(2) - f(1) = -2

→ f(2) - 10 = -2

→ f(2) = 10 -2

→ f(2) = 8

Similarly,

→ f(3) - f(2) = -2

→ f(3) = 8 -2

→ f(3) = 6

<h3>Hence the value of f(3) is 6 .</h3>
DENIUS [597]3 years ago
3 0

Answer:

f(3) = 6

Step-by-step explanation:

Using the recursive rule and f(1) = 10 , then

f(2) = f(1) - 2 = 10 - 2 = 8

f(3) = f(2) - 2 = 8 - 2 = 6

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