A sequence is defined by the recursive function f(n+1)=f(n)-2 If f(1)=10 what is f(3)?
2 answers:
<u>Given </u><u>:</u><u>-</u><u> </u>
- A sequence is defined by f(n + 1) = f(n) -2 .
- f(1) = 10
<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Sol</u><u>u</u><u>tion </u><u>:</u><u>-</u><u> </u>
As per Question ,
→ f(n + 1) = f(n) - 2
→ f(n + 1 ) - f(n ) = -2
Therefore , the second term of the sequence is ,
→ f(2) - f(1) = -2
→ f(2) - 10 = -2
→ f(2) = 10 -2
→ f(2) = 8
Similarly,
→ f(3) - f(2) = -2
→ f(3) = 8 -2
→ f(3) = 6
<h3>
Hence the value of f(3) is 6 .</h3>
Answer:
f(3) = 6
Step-by-step explanation:
Using the recursive rule and f(1) = 10 , then
f(2) = f(1) - 2 = 10 - 2 = 8
f(3) = f(2) - 2 = 8 - 2 = 6
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