Because the probability of getting heads is 1/2, in a scenario in which it is tossed 3 times, the probability of getting exactly one head is 1/3.
Answer:
5.415m and 2.585m long
Step-by-step explanation:
For a right triangle
hyp^2 = opp^2 + adj^2 (Pythagoras theorem)
Given
hypotenuse = 6m
height(opposite) = h meters
Adjacent = (8-h)m
Substitute into the expression above;
6² = h²+(8-h)²
36 = h²+64-16h+h²
36 = 2h²-16h+64
2h²-16h+64-36 = 0
2h²-16h+28= 0
Divide through by 2
h²-8h+14 = 0
Using the general formula
h = 8±√8²-4(14)/2
h = 8±√64-56/2
h = 8±√8/2
h = 8±2.83/2
h = 8+2.83/2 and 8-2.83/2
h = 10.83/2 and 5.17/2
h = 5.415 and 2.585
hence the length of the height of the right triangle are 5.415m and 2.585m long
Answer:
What is da question? >:|
Step-by-step explanation: WHATS DA QUESTION >:P
Answer:
Step-by-step explanation:
Yikes. This is quite a doozy, so pay attention. We will begin by factoring by grouping. Group the first 2 terms together into a set of parenthesis, and likewise with the last 2 terms:
and factor out what's common in each set of parenthesis:
. Now you can what's common is the (d + 3), so factor that out now:
BUT in that second set of parenthesis, we can still find things common in both terms, so we continue to factor that set of parenthesis, carrying with us the (d + 3):
BUT that second set of parenthesis is the difference of perfect squares, so we continue factoring, carrying with us all the other stuff we have already factored:
. That's completely factored, but it's not completely simplified. Notice we have 2 terms that are identical: (d + 3):
is the completely factored and simplified answer, choice 3)
Answer:
≈ 0.97
Step-by-step explanation:
Given that :
Number of green gum drops = 30
Number of Blue gum drops = 1
Total number of gum drops :
(Number of blue + number of green gum drops)
(30 + 1) = 31
Probability = Required outcome / Total possible outcomes
P(green gum drops) = number of green drops / total number of gum drops
P(green gum drops) = 30 / 31 = 0.967 ≈ 0.97
The point x will be drawn slightly to the right of the midpoint between the last two tick marks.
