Answer:
lateral area = 2320 m²
Step-by-step explanation:
The question wants us to calculate the lateral area of a square base pyramid. The square base pyramid has a side of 40 meters.The height is 21 meters.
Half of the square base is 40/2 = 20 meters . With the height it forms a right angle triangle. The hypotenuse side is the slant height of the pyramid.
Using Pythagoras's theorem
c² = a² + b²
c² = 20² + 21²
c² = 400 + 441
c² = 841
square root both sides
c = √841
c = 29 meters
The slant height of the pyramid is 29 meters.
The pyramid has four sided triangle. The lateral area is 4 multiply by the area of one triangle.
area of triangle = 1/2 × base × height
base = 40 meters
height = 29 meters
area = 1/2 × 40 × 29
area = 580
area of one triangle = 580 m²
Lateral area = 4(580)
lateral area = 2320 m²
This is the answer
if substitute 1 and 2 and 3 as x then the points will be :
and that's the picture
good luck
Answer:
<u>The perimeter of the pentagon ≅ 19 units (approximately)</u>
Step-by-step explanation:
Clockwise, starting from the base of the pentagon, we have:
- Base of the pentagon or bottom side ≅ 4 units
- 2nd side ≅ 3.75 units
- 3rd side ≅ 3.75 units
- 4th side ≅ 3.75 units
- 5th side ≅ 3.75 units
In consequence,
Perimeter of the pentagon ≅ 4 + 3.75 + 3.75 + 3.75 + 3.75
<u>Perimeter of the pentagon ≅ 19 units</u>
Answer:
im fairly certain the answer is C
Step-by-step explanation:
you take the base problem, 9-4n and plug in a number for n each time. 9-4(1), 9-4(2), 9-4(3)…
