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Likurg_2 [28]
3 years ago
5

Suppose 20% of the students on campus smoke. you select two students at random. in what percentage of samples will both students

be smokers?
Mathematics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

4%

Step-by-step explanation:

The probability that two smoke is the product of the probabilities that each smokes, provided the students are selected independently.

... 0.20 × 0.20 = 0.0400 = 4%

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7= -5x
exis [7]
Option 2 multiple each side by -5
4 0
3 years ago
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A Gallup survey of 2322 adults (at least 18 years old) in the U.S. found that 408 of them have donated blood in the past two yea
Lelu [443]

Answer: aA 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years = (0.163,0.189)

Step-by-step explanation:

Let p = population proportion of adults in the U.S. who have donated blood in the past two years.

Given: A Gallup survey of 2322 adults (at least 18 years old) in the U.S. found that 408 of them have donated blood in the past two years.

Sample size: n= 2322

Sample proportion q=\dfrac{408}{2322}=0.176

Critical z-value for 90% confidence level : z*=1.645

The confidence interval for population proportion:

q\pm z^*(\sqrt{\dfrac{q(1-q)}{n}})

A 90% confidence interval for the population proportion of adults in the U.S. who have donated blood in the past two years:

0.176\pm (1.645)(\sqrt{\dfrac{0.176(1-0.176)}{2322}})\\\\=0.176\pm (1.645)(0.0079)\\\\=(0.176\pm0.013)\\\\=(0.176-0.013,0.176+0.013))\\\\=(0.163,0.189)

Hence,

6 0
3 years ago
(5a + a2 - 14) (10a + a2 + 39)
yan [13]
15a+a4+25 is the answer
8 0
3 years ago
PLEASE HELP, PICTURE ATTACHED! ANSWER CHOICE!
Alina [70]

The answer is D. 13 Inches, this is 6th grade math I believe?

6 0
3 years ago
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When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan
vitfil [10]

Answer:

a = 6m/s^2

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

a\ \alpha\ \frac{1}{m}

Convert variation to equality

a = \frac{F}{m}; Where F is the constant of variation (Force)

Make F the subject of formula;

F = ma

When mass = 4kg; Acceleration = 15m/s²

F = 4 * 15

F = 60N

When mass = 10kg; Substitute 60 for Force

F = ma

60 = 10 * a

60 = 10a

Divide both sides by 10

\frac{60}{10} = \frac{10a}{10}

a = 6m/s^2

<em>Hence, the acceleration is </em>a = 6m/s^2<em />

4 0
3 years ago
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