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KatRina [158]
3 years ago
12

1 fourth to the 3rd power as a fraction

Mathematics
2 answers:
lukranit [14]3 years ago
7 0
1/64 is the answer as a fraction
CaHeK987 [17]3 years ago
4 0
1/64! i think is the correct answer! have a good day
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Use the interactive ruler to measure the distance from the center of dilation, C, to the image and pre-image. The distance from
inna [77]

the answer is : 4, 2, one-half.

7 0
3 years ago
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A vehicle purchased for $ 27500 depreciates at a constant rate of 4 % . Determine the approximate value of the vehicle 12 years
Anna35 [415]

Answer:

$13,200

Step-by-step explanation:

Multiply the original cost by .04 and 12 years

(original cost)(rate in decimal form)(time)

6 0
3 years ago
Suppose that 15 inches of wire costs 90 cents. At the same rate, how many inches of wire can be bought for 48 cents?
tamaranim1 [39]
This can be solved by making an equivalent ratio.
The original ratio is what we know, 15 inches of wire for 90 cents.
In a ratio of inches of wire:cents, this would be 15:90.

Now for the equivalent ratio.
We don't know the number in the inches place but we do know it for the cents place.
Let's use x to represent inches of wire.
x:48 is our new ratio, and we need to find x.

Since x:48 and 15:90 are equivalent, that means the same thing that was done to 90 to get 48 has to be done to 15 to get the value of x, since the same thing must be applied to both sides.
We can find what 90 was divided by (which is what we'll have to divide 15 by) by dividing 90 by 48.
90 / 48 = 1.875

This means 48 • 1.875 = 90 and x • 1.875 = 15.
Since we don't know x though, we can isolate it by dividing both sides by 1.875.
x • 1.875 = 15
x • 1.875 / 1.875 = x
15 / 1.875 = 8
So x is 8.

Answer:
While you can be 15 inches of wire for 90 cents, you can buy 8 inches of wire for 48 cents at the same rate.
3 0
3 years ago
Let t(x) = 3x-8 and s(t(x)) = x^2 + 3x - 2. Find s(1).
ratelena [41]
<h3>Answer:  16</h3>

=============================================================

Explanation:

Equate s(t(x)) and s(1) to find that t(x) = 1 must be the case.

Let's find what x must be.

t(x) = 3x-8

1 = 3x-8

1+8 = 3x

9 = 3x

3x = 9

x = 9/3

x = 3

So plugging x = 3 into t(x) gets us t(x) = 1

In other words, t(3) = 1

So that tells us s(t(3)) = s(1)

-------------

Let's plug x = 3 into the s(t(x)) equation

s(t(x)) = x^2 + 3x - 2

s(t(3)) = (3)^2 + 3(3) - 2

s(1) = 9 + 3(3) - 2

s(1) = 9 + 9 - 2

s(1) = 18 - 2

s(1) = 16

7 0
3 years ago
Becky says that lines c and d are parallel.
katen-ka-za [31]

A) angle 1 = angle 2 - Incorrect

These angles are only on one of the following lines, which means that they do not show that lines C and D are parallel. In addition, angles 1 and 2 are supplementary, so they could not be equal.

B) angle 1 + angle 2 = 180 - Incorrect

Though this is true, this does not prove that lines C and D are parallel because both of these angles are on the same line.

C) angle 2 = angle 3 - Correct

These angles are alternate interior angles and there are angles on both lines, which proves that lines C and D are parallel.

D) angle 2 + angle 3 = 180 - Incorrect

These angles are equivalent, so they cannot add up to 180 degrees unless the intersecting line was perpendicular to both lines C and D.

Hope this helps!! :)

5 0
3 years ago
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