A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
(6g^4h^5)^2. We have to square each term individually. Remember, squaring an exponent is just multiplying the exponents together.
6^2 = 36
(g^4)^2 = g^8
(h^5)^2= h^10
The final answer: 36g^8h^10
The answer is x=9 because if you do 3x+-2 that gives you 1 and 1 divided by 9 is 9 and you get that by getting rid of your 6 first and adding it to the 3 from 3(x+1)
Answer:
D
Step-by-step explanation:
Answer: Neither
Step-by-step explanation:
y = -5/4 x + 3/4
y = 5/4 x + 3/4
Because -5/4 is not a negative reciprocal of 5/4 and because they are not the same, they are neither in parallel or perpendicular
