Which of these values of x is NOT a solution of the equation tanx= 1?

Mathematics

1 answer:

Kobotan [32]2 years ago

5 0

The tangent ratio is an illustration of the trigonometry identity

The value of x that is not a solution of tan(x) = 1 is 3 $\pi$ /4

<h3>How to determine the value that is not a solution</h3>

The trigonometry identity is given as:

tan(x) = 1

Next, we test the x values using a calculator.

When $x = -7\pi/4$ , we have:

tan(-7 $\pi$ /4) = 1

When x = 3 $\pi$ /4, we have:

tan(3 $\pi$ /4) = -1

When x = 5 $\pi$ /4, we have:

tan(5 $\pi$ /4) = 1

When x = $\pi$ /4, we have:

tan( $\pi$ /4) = 1

Hence, the value of x that is not a solution of tan(x) = 1 is 3 $\pi$ /4

Read more about trigonometry identity at:

brainly.com/question/7331447

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Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the

Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

$y=Ce^{kt}$ . We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is $\frac{dy}{dt}$ . Thus, the change in the concentration of salt is found in

$\frac{dy}{dt}=$ inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

$3(\frac{y}{400})$