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lbvjy [14]
3 years ago
12

Find the area of the triangle.

Mathematics
2 answers:
DENIUS [597]3 years ago
7 0

Answer:

10.92

Step-by-step explanation:

-----------------------

Pie3 years ago
3 0
The answer to your question is A 21.84cm2
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12/19*.............................= -12/19
melamori03 [73]

Answer:

\frac{12}{19} \times \underline{\bold{-1}} = -\frac{12}{19}

Step-by-step explanation:

\frac{12}{19} \times ..... = -\frac{12}{19}

= \frac{\frac{12}{19}}{-\frac{12}{19}}

= \frac{12}{19} \times -\frac{19}{12}

= -\frac{228}{228}

= \bold{-1}

So, the appropriate value to complete it is -1

#CMIIW ^^

3 0
3 years ago
A 5-column table has 4 rows. The first column has entries A, B, C, Total. The second column is labeled X with entries 15, 5, 30,
Ugo [173]

Answer:

A and X

Step-by-step explanation:

Got it right on edge-nuity

8 0
3 years ago
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The ruby throated hummingbird has a wingbeat of about 200 beats per second about how many wing Beats would a hummingbird have in
Nady [450]
36,000 wing beats

60 sec= 1 minute 60*3=180sec/3minutes

180*200=36,000

4 0
3 years ago
Simplify. Your answer should contain only positive<br> exponents.<br> -2^х
polet [3.4K]

Answer: I'm not entirely sure, but maybe 1/x^2?

8 0
3 years ago
A dog chases a squirrel. The dog is originally 200 feet away from the squirrel. The dog's speed is 150 feet per minute. The squi
Dafna11 [192]

Answer:

15 seconds

Step-by-step explanation:

If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy:  the dog's rate is 150 and the squirrel's is 100.  The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know:  the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up.  Since we don't know what d is, we will just call it d!  Now it seems as though we have 2 unknowns which is a problem.  However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other.  Here's the dog's equation:

d = rt

d+200 = 150t

And the squirrel's:

d = 100t

If we solve both for t and set them equal to each other we have:

\frac{150}{d+200} =\frac{100}{d}

Now we can cross multiply to solve for d:

150d = 100d + 20,000 and

50d = 20,000

d = 400

But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took.  So sub that d value back into one of the equations we have solved for t and do the math:

t=\frac{100}{d}=\frac{100}{400} =\frac{1}{4}

That's 1/4 of a minute which is 15 seconds.

6 0
3 years ago
Read 2 more answers
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