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vesna_86 [32]
3 years ago
6

The graph of a function f is given. Use the graph to estimate the following. (Enter your answers using interval notation.)

Mathematics
1 answer:
kirill [66]3 years ago
6 0

Using the graph and function concepts, it is found that:

a) The domain is [-5,4], while the range is [-2,-5]

b) The function is increasing in [0,1] and [2,3], and decreasing [-5,0], [1,2], and [3,4].

--------------------

  • The domain of a function is given by it's input values, that is, the values of x, the horizontal axis on the <em>graph</em>.
  • The range of a function is given by it's output values, that is, the values of y, the vertical axis on the <em>graph</em>.
  • If the <em>graph </em>is pointing upwards, the function increases.
  • If the <em>graph </em>is pointing downwards, the function decreases.

--------------------

Item a:

  • On the graph, the x-values are from -5 to 4, thus the domain is: [-5,4]
  • The y-values are from -2 to -5, thus, the range is: [-2,-5]

--------------------

Item b:

  • On the graph, it is pointing upwards on the following intervals, for x-values: From 0 to 1, and from 2 to 3, thus, the function is increasing in [0,1] and [2,3].
  • On the other intervals,  [-5,0], [1,2], and [3,4], the function is decreasing.

A similar problem is given at brainly.com/question/10891721

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The sum of the present ages of the mother and her daughter is 80 years. The mother was thrice as old as her daughter when she wa
Alika [10]

Answer:

let the daughter age be x

let mother age be 3x

Step-by-step explanation:

x+3x= 80

4x = 80

x= 80\4

x=20

daughter age is 20

mather age= 80 -20

= 60

daughter age 20

mother age 60

7 0
2 years ago
Using the completing-the-square method, rewrite f(x) = x2 − 8x + 3 in vertex form.
lys-0071 [83]
          f(x) = x² - 8x + 3
             y = x² - 8x + 3
           - 3                - 3
        y - 3 = x² - 8x + 16
y - 3 + 16 = x² - 8x + 16
     y + 13 = x² - 8x + 16
     y + 13 = (x - 4)²
         - 13      - 13
             y = (x - 4)² - 13
          f(x) = (x - 4)² - 13
8 0
2 years ago
Which term describes a function in which the y-values form a geometric sequence
romanna [79]
The geometric sequence is a sequence in which the proceeding number is equal to the preceeding number multiplied by a ratio. The expression that represents this sequence is an = a1*r^(n-1) where r is the ratio and n is an integer. This type of formula is exponential
8 0
3 years ago
Question 1 options:<br><br> 3<br><br><br> 8<br><br><br> 12<br><br><br> 2.5
rewona [7]

Answer:

2.5

Step-by-step explanation:

(I'm assuming you're doing this the same way I learned it, if not I'm sorry if it doesn't make sense)

\frac{2}{x}=\frac{12}{15}

Cross multiply

12x=30

Divide

x=2.5

This is just one way to do the problem. An easier way is to simplify the fractions.

\frac{2}{x}=\frac{4}{5}

You can either cross multiply or figure out that 2 is half of four and simply divide 5 by 2 which will also result in 2.5

5 0
2 years ago
F(3) = 8; f^ prime prime (3)=-4; g(3)=2,g^ prime (3)=-6 , find F(3) if F(x) = root(4, f(x) * g(x))
Marrrta [24]

Given:

f(3)=8,f^{\prime}(3)=-4,g(3)=2,\text{ and }g^{\prime}(3)=-6

Required:

We\text{ need to find }F^{\prime}(3)\text{ if }F(x)=\sqrt[4]{f(x)g(x)}.

Explanation:

Given equation is

F(x)=\sqrt[4]{f(x)g(x)}.F(x)=(f(x)g(x))^{\frac{1}{4}}F(x)=f(x)^{\frac{1}{4}}g(x)^{\frac{1}{4}}

Differentiate the given equation for x.

Use\text{ }(uv)^{\prime}=uv^{\prime}+vu^{\prime}.\text{  Here u=}\sqrt[4]{f(x)}\text{ and v=}\sqrt[4]{g(x)}.

F^{\prime}(x)=f(x)^{\frac{1}{4}}(\frac{1}{4}g(x)^{\frac{1}{4}-1})g^{\prime}(x)+g(x)^{\frac{1}{4}}(\frac{1}{4}f(x)^{\frac{1}{4}-1})f^{\prime}(x)=\frac{1}{4}f(x)^{\frac{1}{4}}g(x)^{\frac{1}{4}-\frac{1\times4}{4}}g^{\prime}(x)+\frac{1}{4}g(x)^{\frac{1}{4}}f(x)^{\frac{1}{1}-\frac{1\times4}{4}}f^{\prime}(x)=\frac{1}{4}f(x)^{\frac{1}{4}}g(x)^{\frac{1-4}{4}}g^{\prime}(x)+\frac{1}{4}g(x)^{\frac{1}{4}}f(x)^{\frac{1-4}{4}}f^{\prime}(x)F^{\prime}(x)=\frac{1}{4}f(x)^{\frac{1}{4}}g(x)^{\frac{-3}{4}}g^{\prime}(x)+\frac{1}{4}g(x)^{\frac{1}{4}}f(x)^{\frac{-3}{4}}f^{\prime}(x)

Replace x=3 in the equation.

F^{\prime}(3)=\frac{1}{4}f(3)^{\frac{1}{4}}g(3)^{\frac{-3}{4}}g^{\prime}(3)+\frac{1}{4}g(3)^{\frac{1}{4}}f(3)^{\frac{-3}{4}}f^{\prime}(3)Substitute\text{ }f(3)=8,f^{\prime}(3)=-4,g(3)=2,\text{ and }g^{\prime}(3)=-6\text{ in the equation.}F^{\prime}(3)=\frac{1}{4}(8)^{\frac{1}{4}}(2)^{\frac{-3}{4}}(-6)+\frac{1}{4}(2)^{\frac{1}{4}}(8)^{\frac{-3}{4}}(-4)F^{\prime}(3)=\frac{-6}{4}(8)^{\frac{1}{4}}(2^3)^{\frac{-1}{4}}+\frac{-4}{4}(2)^{\frac{1}{4}}(8^3)^{\frac{-1}{4}}F^{\prime}(3)=\frac{-3}{2}(8)^{\frac{1}{4}}(8)^{\frac{-1}{4}}-(2)^{\frac{1}{4}}(8^3)^{\frac{-1}{4}}F^{\prime}(3)=\frac{-3}{2}\frac{\sqrt[4]{8}}{\sqrt[4]{8}}-\frac{\sqrt[4]{2}}{\sqrt[4]{8^3}}F^{\prime}(3)=\frac{-3}{2}-\frac{\sqrt[4]{2}}{\sqrt[4]{(2)^9}}F^{\prime}(3)=\frac{-3}{2}-\frac{\sqrt[4]{2}}{\sqrt[4]{(2)^4(2)^4}(2)}F^{\prime}(3)=\frac{-3}{2}-\frac{\sqrt[4]{2}}{4\sqrt[4]{}(2)}F^{\prime}(3)=\frac{-3}{2}-\frac{1}{4}F^{\prime}(3)=\frac{-3\times2}{2\times2}-\frac{1}{4}F^{\prime}(3)=\frac{-6-1}{4}F^{\prime}(3)=\frac{-7}{4}

Final answer:

F^{\prime}(3)=\frac{-7}{4}

8 0
11 months ago
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