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vesna_86 [32]
3 years ago
6

The graph of a function f is given. Use the graph to estimate the following. (Enter your answers using interval notation.)

Mathematics
1 answer:
kirill [66]3 years ago
6 0

Using the graph and function concepts, it is found that:

a) The domain is [-5,4], while the range is [-2,-5]

b) The function is increasing in [0,1] and [2,3], and decreasing [-5,0], [1,2], and [3,4].

--------------------

  • The domain of a function is given by it's input values, that is, the values of x, the horizontal axis on the <em>graph</em>.
  • The range of a function is given by it's output values, that is, the values of y, the vertical axis on the <em>graph</em>.
  • If the <em>graph </em>is pointing upwards, the function increases.
  • If the <em>graph </em>is pointing downwards, the function decreases.

--------------------

Item a:

  • On the graph, the x-values are from -5 to 4, thus the domain is: [-5,4]
  • The y-values are from -2 to -5, thus, the range is: [-2,-5]

--------------------

Item b:

  • On the graph, it is pointing upwards on the following intervals, for x-values: From 0 to 1, and from 2 to 3, thus, the function is increasing in [0,1] and [2,3].
  • On the other intervals,  [-5,0], [1,2], and [3,4], the function is decreasing.

A similar problem is given at brainly.com/question/10891721

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kap26 [50]

Answer:

73.4846922835 = 73.5 and no it is not a perfect square 5400/100 = 54

8 0
3 years ago
A rectangle has an area of 24 square units and a side length of 2 3/4 units. Find the other side length of the rectangle. (Answe
Paul [167]
The answer is 8 8/11
4 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!
Nataliya [291]

Answer:

  • Perimeter = 22*sqrt(2)
  • Area = 60.5 inches
  • D

Step-by-step explanation:

Remark

You need 2 facts.

  1. A square has 4 equal sides.
  2. It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

  • a^2 + a^2 = c^2
  • 2a^2 = c^2

Givens

  • c = 11

Solution

  • 2a^2 = 11^2
  • 2a^2 = 121                    Divide by 2
  • a^2 = 121/2                  Take the square root of both sides
  • sqrt(a^2) = sqr(121/2)    
  • a = 11/sqrt(2)                Rationalize the denominator
  • a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
  • a = 11 * sqrt(2) / 2

<em><u>Perimeter</u></em>

P = 4s

  • P = 4*11*sqrt(2)/2
  • P = 44*sqrt(2)/2
  • P = 22*sqrt(2)

You don't need the area. The answer is D

<em><u>Area</u></em>

  • Area = s^2
  • Area = (11*sqrt(2)/2 ) ^2
  • Area = 121 * 2 / 4
  • Area = 60.5


8 0
3 years ago
A cylinder's volume can be calculated by the formula V=Bh, where V stands for volume, B stands for base area, and h stands for h
Anastaziya [24]

Answer:

h = 3x^5-3x^2-10\text{ units}

Step-by-step explanation:

We are given the following in the question:

Volume of cylinder =

V=Bh

where B is the area of base and h is the height of cylinder.

Volume of cylinder =

V = 6\pi x^7-6\pi x^4-20\pi x^2

Base area =

B = 2\pi x^2

We have to find height of cylinder.

h = \dfrac{V}{B}\\\\h = \dfrac{6\pi x^7-6\pi x^4-20\pi x^2}{2\pi x^2}\\\\h = 3x^5-3x^2-10\text{ units}

Thus, the height of cylinder is 3x^5-3x^2-10 units.

6 0
3 years ago
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