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fiasKO [112]
2 years ago
9

Solve the following system of equations algebraically: Y = x^2 + 8x – 9 Y = 2x + 7

Mathematics
1 answer:
julia-pushkina [17]2 years ago
3 0
Use simultaneous equations:
2x + 7 = x^2 + 8x - 9
7 = x^2 + 6x - 9
16 = x^2 + 6x
+ or - 4 = 7x
answer is
-4/7 or 4/7
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3.Write the product as a trinomial. (2r – 5)(r + 10)
Maurinko [17]
B is the correct answer

5 0
3 years ago
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keon ha some change in his pocket then a friend loaned him 0.25 now keon has 1.45 in his pocket which equation can be used to fi
Studentka2010 [4]

Answer:

$1.45-$0.25=x

x=$1.20

Step-by-step explanation:

3 0
3 years ago
How do you solve this??
vovikov84 [41]

Answer:

The sum of this entire line is 180, so to solve this we would subtract 20 from 180, which means x = 160.

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2 years ago
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PLEASE HELP SUPER FAST WORTH ALOT OF POINTS
lutik1710 [3]

Answer:

1) 78.87%

2) 99.7%

Step-by-step explanation:

The z-score for a normal distribution is given by:

z=\frac{X-\mu}{\sigma}

1- The given data is:

σ = 4 years

μ = 50 years

For X = 45 and X =55

z_1=\frac{45-50}{4}\\z_1=-1.25\\z_2=\frac{55-50}{4}\\z_2=1.25

A z-score of -1.25 corresponds to the 10.57th percentile of a normal distribution, while a z-score of 1.25 is equivalent to the 89.44th percentile.

Therefore, the percentage of the alligators are between 45 and 55 years old is:

P=89.44-10.57=78.87\%

78.87% of alligators.

2- The given data is:

σ = 2 minutes

μ = 17 minutes

For X = 11 and X =23

z_1=\frac{11-17}{2}\\z_1=-3\\z_2=\frac{23-17}{2}\\z_2=3

A z-score of -3.0 corresponds to the 0.135th percentile of a normal distribution, while a z-score of 3.0 is equivalent to the 99.865th percentile.

Therefore, the percentage of people that should be seen by the doctor between 11 and 23 minutes is:

P=99.865-.0135=99.73\%

99.7% of people.

3 0
3 years ago
Nicolas weighs 37 kilograms 95 grams. Jacques weighs 4,650 grams less than Nicolas. How much does Jacques weigh?
slava [35]

Step-by-step explanation:

convert to g

37 095 g

37 095-4650=32 445 g / 32.455 kg

3 0
3 years ago
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