Answer:
1 is 1/2 5 is 2 1/2 and 7 would be 3 1/2
Step-by-step explanation:
Answer:
The circumference of Meg’s picture frame is the perimeter of Pam’s picture frame by approximately 0.65 ft
Step-by-step explanation:
Pam's picture frame : Square with area of 3 sq. foot
Meg’s picture frame is a circle with a radius, r of 1 foot.
The circumference of Meg’s picture frame is the perimeter of Pam’s picture frame by approximately feet.
Let's calculate circumference of Meg's picture frame:
Circumference c, = 2πr
r = 1 ft
c = 2 * 3.14 *1 = 6.28 ft
Now calculate Perimeter of Pam's picture frame:
A is area of square and s is the side
A = s²
s² = 3
s = √3
Permeter of square = 4s
= 4√3 = 6.93ft
Now in order to find circumference of Meg’s picture frame is the perimeter of Pam’s picture frame, we have to find their difference.
Permimeter of square frame - Circumference of circle frame = 6.93 - 6.28 = 0.65
No
I think that’s it(sorry if I’m wrong)
Answer:
5.4
Explanation:
I multiplied 18.6 by the answer choices that should give me 100.44. But the shortcut to this is to divide the area by it’s height.
Explanation:
There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.
<u>Statement</u> . . . . <u>Reason</u>
2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle
3. AD ≅ BD
and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle
4. ∠CAE = ∠CAD +∠DAE
and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate
5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality
6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality
7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality
8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate
9. ∠ACD ≅ ∠BCD . . . . CPCTC
10. DC bisects ∠ACB . . . . definition of angle bisector
