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2 years ago

13

Select all the correct graphs. Which graphs are the graphs of even functions?

1 answer:

natali 33 [55]2 years ago

7 0

Answer:

I think it the first one is

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Nikki earned $185 at her summer job she already had savings of $125.75 she buys a t shirt for 23.50 how much money does she have

vodka [1.7K]

She has $287.25 after buying the shirt

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3 years ago

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Goryan [66]

Answer:

6. 10

Step-by-step explanation:

6 0

3 years ago

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

<u>(a) Length of AB</u>

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

3 years ago

What is [[3^3-7)·5)/10]+((1+3+6+9)-)]

yanalaym [24]

Answer:

$\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28$

Step-by-step explanation:

As far as I am able to observe from the statement of your question, the expression is:

$\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)$

So, lets solve this expression, which anyways would clear your concept

Considering the expression

$\left[[\left(3^3-7\right)\cdot \frac{5}{10}\right]+\left(\left(1+3+6+9\right)-1\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1$

Lets first solve $\left(3^3-7\right)\frac{5}{10}$

As $3^3=27$

$=\frac{5}{10}\left(27-7\right)$

$=\frac{1}{2}\left(27-7\right)$

$=20\cdot \frac{1}{2}$

$=10$

So,

$\left(3^3-7\right)\frac{5}{10}+1+3+6+9-1 = 10+1+3+6+9-1$

= $28$

Therefore,

$\left(\left(3^3-7\right)\frac{5}{10}\right)+\left(\left(1+3+6+9\right)-1\right)=28$

Keywords: Expression solving

Learn more about solving expression from brainly.com/question/4687406

#learnwithBrainly

7 0

3 years ago

Four milliliters of ink A is added to 10 milliliters of ink B, forming a mixture of inks. Ink A contains 10% blue pigment. Ink B

DochEvi [55]

The question involves what is referred to as a mass balance and can be solved as follows:
Ink A is:
total = 4ml
blue = 4 x 0.1 = 0.4ml
remaining = 3.6ml
Ink B is:
total = 10ml
blue = x
Remaining = 10 - x
Now, upon combination:
total = 4ml + 10ml = 14ml
Blue = 14ml * 0.35 = 4.9ml
Blue in total = blue in A + blue in B
4.9 = 0.4 + x
x = 4.5ml
Percentage of blue ink in B = 4.5/10 x 100
= 45%
The answer is A

5 0

4 years ago

Read 2 more answers