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3 years ago

PLEASE HELP THIS IS URGENT !

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

4, 9, 16, 25, 36, 49, 64, 81, 100, 121

a negative times a negative is a positive and squaring those numbers would be multiplying a negative by itself.

For example (-2)*(-2) is 4

**note, this only applies if the negative value is in the parentheses. (-2)^2 is different than -2^2 because with -2^2 only the 2 is getting squared and then you’d have to multiply the negative after**

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in a class of 25 students 8% of the students play on a softball team how many students play on the softball team

Alla [95]

2 students play on the softball team

<u>Solution:</u>

Given that in a class of 25 students, 8 % of students play on a softball team

To find: Number of students play on softball team

Total number of students in class = 25

8 % of students play on a softball team means that 8 % of total students play on softball team

Therefore, number of students play on softball team is given as:

$\rightarrow 8 \% \text{ of } 25\\\\\rightarrow 8 \% \times 25\\\\\rightarrow \frac{8}{100} \times 25\\\\\rightarrow \frac{8}{4} = 2$

Thus 2 students play on the softball team

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3 years ago

So I was wondering if any of y'all could help me with this:

notsponge [240]

Step-by-step explanation:

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4 years ago

There was 7L punch for the birthday party. How many mL punch was there?

kotykmax [81]

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3 years ago

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- 5/2 divided by 5)7

Anastasy [175]

Answer:

-7/2

Step-by-step explanation:

6 0

3 years ago

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How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
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\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
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\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
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\textit{and let us use "x" again below}
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\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$

8 0

3 years ago