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3 years ago

PLEASE HELP THIS IS URGENT !

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

4, 9, 16, 25, 36, 49, 64, 81, 100, 121

a negative times a negative is a positive and squaring those numbers would be multiplying a negative by itself.

For example (-2)*(-2) is 4

**note, this only applies if the negative value is in the parentheses. (-2)^2 is different than -2^2 because with -2^2 only the 2 is getting squared and then you’d have to multiply the negative after**

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What is the solution to the following equation?

Pachacha [2.7K]

Answer:

x = 4

Step-by-step explanation:

8x - 9 = 6x - 1

Bring variables to the left side, whereas numbers to the right.

8x - 6x = - 1 + 9

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3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

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3 years ago

I need help with these 2 problems. Please and thank you :)

dsp73

Answer:

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Step-by-step explanation:

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2 years ago

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