<h3>I'll teach you how to solve your two equations</h3>
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(A)
a^3*b^4*5^4/b^2*5
Apply exponent rule:
5^4 a^3 b^4-2/5
Subtract the numbers:
4-2= 2
5^4 a^3 b^2/5
Cancel the common factor 5:
5^3 a^3 b^2
5^3= 125
125a^3b^2
Your Answer is
(B)
x^15y^9/x^8y^3
Apply exponent rule:
y^9 x^15-8/y^3
Subtract the numbers:
15-8= 7
x^7y^9/y^3
Apply exponent rule:
x^7y^9-3
Subtract the numbers:
9-3= 6
x^7y^6
Your Answer Is
Plz mark me as brainliest if this helped :)
If you’re asking to solve y=-x+5 it would be x=5
i’m sorry if you was asking something else
None of the <em>three</em> points (A, B, C) lies on the circumference of the <em>unit</em> circle.
<h3>What point is in the circumference of an unit circle?</h3>
<em>Unit</em> circles are circles centered at the origin and with a radius of 1. A point is on the circumference if and only if the distance of the point respect to the origin is equal to 1. The distance of each point is determine by Pythagorean theorem:
Point A
d = 5
Point B
d = √29 /10
d ≈ 0.539
Point C
d = √58 /4
d ≈ 1.904
None of the <em>three</em> points (A, B, C) lies on the circumference of the <em>unit</em> circle.
<h3>Remark</h3>
The statement presents a typing mistake, correct form is shown below:
<em>A(x, y) = (4, 3), B(x, y) = (1/2, 1/5), C(x, y) = (3/4, 7/4). Which point lies on the circumference of the unit circle?</em>
To learn more on circles: brainly.com/question/11987349
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Answer:
B
Step-by-step explanation:
all the values should be decreased by 5 for each outcome