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Agata [3.3K]
3 years ago
8

Gallon of gas: $2.15, 15% markup

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0
The answer would be $2.47
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4. The figure shows a rectangle with a width of 6k inches. The length of the rectangle is 4 inches shorter than the width.
vesna_86 [32]

Answer:

C.

Step-by-step explanation:

sorry if its not correct but i hope it helps

8 0
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10 lb 6oz minus 7lb 11oz is
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(10 lb 6 oz)-(7 lb 11 oz) = 2.6875 lb
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Which equation represents the graph. Please help I’m trying to finish a post test for math
8090 [49]

Answer:

5(x+3) is your answer

Step-by-step explanation:


3 0
3 years ago
Write a function number_of_pennies() that returns the total number of pennies given a number of dollars and (optionally) a numbe
seraphim [82]
Ok, first of all, it is important to understand that this function would depend on 2 variables; the number of dollars (x) and the number of pennies (y). Every dollar is equivalent to 100 pennies. So, if we are given x dollars, we have 100*x pennies. If we also have y pennies, we still get y pennies. We need to add these two to get the total amount of pennies. Thus, the correct function is:
f(x,y)=100*x+y
7 0
3 years ago
Integrate 1 - x / x(x2 + 1) d x by partial fractions.
solniwko [45]

Answer:

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

Step-by-step explanation:

step 1:-   by using partial fractions

[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }......(1)

<u>step 2:-</u>

solving on both sides

1-x=A(x^{2} +1)+(Bx+C)x......(2)

substitute x =0 value in equation (2)

1=A(1)+0

<u>A=1</u>

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

<u>-</u>1  =  C

<u>step 3:-</u>

substitute A,B,C values in equation (1)

now  

\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 }  d x -\int\limits \frac{1}{x^{2}+1 }  d x

by using integration formulas

i)  by using \int\limits \frac{1}{x}   d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\.....(b)

\int\limits tan^{-1}x  dx =\frac{1}{1+x^{2} } +C.....(c)

<u>step 4:-</u>

by using above integration formulas (a,b,and c)

we get answer is

log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x

6 0
3 years ago
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