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nika2105 [10]
2 years ago
15

PLEASE HELP!!! 1. Use the figure below to answer the questions. (a) Solve for x.

Mathematics
1 answer:
vredina [299]2 years ago
8 0

Answer:

335° because all the sides added up is 565 and 900-565= 335°

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15,000 invested at a rate of 4.8% compounded monthly. Write a compound interest function to model the situation . Then find the
Soloha48 [4]

Answer 565

Step-by-step explanation:

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2 years ago
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A wheel turns through 90 revolutions per minute how many degrees does it turn through in 1 second
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Answer:

540°

Step-by-step explanation:

90 revolutions = 360°×90 = 32400°

32400° in 60 sec or 1 min

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If Sarah had eight apples and she ate two apples how many apples did she eat
MAVERICK [17]
She ate two apples. Six apples would be left if you subtracted 2 from 8.
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2 years ago
A standard six-sided die is rolled onto a table. The product of the visible numbers is 144. What is the number on the bottom sid
denis-greek [22]
<h3>Answer:  5</h3>

Explanation:

This is something you could do by trial and error.

The visible numbers are 1,2,3,4,6 which multiply to 144.

Another approach is to notice that 5 is not a factor of 144, so it must be the hidden value not part of the items multiplied.

Every other number 1,2,3,4,6 is a factor of 144.

1*144 = 144

2*72 = 144

3*48 = 144

4*36 = 144

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8 0
2 years ago
Math:<br> Please help me I don’t understand and I need to do corrections.
GREYUIT [131]
So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
{2}^{2}  \times 3 \times 5 \\ and \\  {2}^{2}  \times  {3}^{2}  \times 5 \times 7
each have two twos. both have one 5, so we know our answer will look something like
{2}^{2}  \times 5 \times other \: stuff
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

one has one 3 and one has two, so we need two threes. now our equation is
{2}^{2}  \times {3}^{2}  \times 5 \times stuff

what's the only number we have to deal with? 7...

how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
4 0
2 years ago
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