Solve: -2(4g - 3) = 30 * 1 point g = 4 g = -4 g = 2 g = -3

For the pair of vectors, find U.V. U=-2i V=4i

maks197457 [2]

Answer:

8

Step-by-step explanation:

If you want the dot product, here it is: (0)(0) + (-2i)(4i) = 8

6 0

4 years ago

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam

Aleksandr-060686 [28]

Answer:

advance tickets $30.00

same day tickets $35.00

Step-by-step explanation:

1. In this equation, you are trying to find two values so you must use system of equations. Your two equations would be:

40x +20y = 1900

x + y = 65

x represents the price of advance tickets and y represents the price of same day tickets.

2. Solve the equation by performing elimination using multiplication. Multiple one equation by a constant to get two equations that contain opposite terms.

40x + 20y = 1900

-40(x + y = 65) → -40x + -40y = -2600

3. Add the equations, eliminating one variable. (add -40x + -40y = -2600 to 40x + 20y = 1900)

40x + 20y = 1900

+ -40x + -40y = -2600

Results in: -20y = -700

Solve for y by dviding both sides by -20.

y = 35

4. Substitute the solved value into one of the equations and solve for the remaining variable.

x + 35 = 65

Subtract 35 from both sides to solve for x.

x = 30

The advance tickets were $30.00 and the same day tickets were $35.00.

7 0

3 years ago

How to graph transformations of quadratic functions

miskamm [114]

Answer:

Shift "h" units to the right, "k" units up, and reflect over the x or y axis when needed.

Step-by-step explanation:

1) I want to talk about reflections first.

Reflections across the x-axis --> $y = ax^2$ , a is the coefficient. if a is negative, then the equation should be reflected across the x-axis. This is known as a vertical reflection.
Reflections across the y-axis --> $y=a(bx)^2$ , b is the coefficient. If b is negative, then reflect the equation over the y-axis. There are cases where the reflection across the y-axis does not change anything. But, let's say its $y=(x-3)^2$ ... the reflection across the y-axis is different (that equation is: $y=(-x-3)^2$ )

2) Rigid transformations

Horizontal transformations (to the left or right): $y=a(bx-h)^2$ , factor out b from "bx-h" and whatever h equals is the units to the right. If h is a negative number, then you move to the left.
Vertical transformations (up and down): $y = a(bx-h)^2+k$ ... k is just the units up... if k is negative then we move it down.

Example (check image for visual)

We transform $y = x^2$ to $y = -(-x-3)^2+3$ , you move right 3, then reflect across the x-axis, then reflect across y-axis, then move 3 up.

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Note: In the image, the red line is the original function, the blue one is the transformed function. See if you can follow along with the verbal instructions I gave above.