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Stells [14]
3 years ago
11

Which organelle stores water and helps to maintain the plant cell shape? C D B E A F G H

Biology
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

H. Vacuole.

Explanation:

Vacuole is the organelle that is responsible for storing of water and helps to maintain the shape of plant cell. Plant cell has one large vacuole that maintain water balance in plant cell. vacuoles are also used to store cellular fuel by some cells in animals, plants, and microorganisms. In animals, vacuole is small and responsible for the storing of waste products that are produced in the cell.

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A pink snapdragon is crossed to a white snapdragon. What is the probability of getting a red snap dragon
Crazy boy [7]

Answer:

0%

Explanation:

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6 0
3 years ago
The relationship between the insect hormones ecdysteroid and PTTH is an example of ________. A. an interaction of the endocrine
Paraphin [41]

The correct example about the relationship between the insect hormones ecdysteroid and PTTH is interaction of the endocrine and nervous system. Hence, Option A is correct.

ENDOCRINE SYSTEM:

It is a complex system which is under hormonal control. Hormones are released by the glands and it cordinates body functions from metabolism to growth and development.

NERVOUS SYSTEM:

It is a complex system consisting of organised group of cells called neurons that carry messages from brain and spinal cord to other various body parts.

As PTTH (prothoracicotropic hormone)  stimulates prothoracic gland of an insect that triggers the release of ecdysone hormone for the stimulation there should be an neuroendocrine mechanism.                                      Thus, Option A is correct.

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7 0
1 year ago
if a neuron had a mutation that prevented the production of voltage gated Na+ channels, what function would the neuron NOT be ab
NISA [10]
The answer is generation and propagation of action potential.

Na+ channels are important for generation and propagation of action potential. In normal neurons, when neurons hit threshold and action potential is triggered, the Na+ channels open and Na+ ions enter the neuron. After the depolarization of membrane, Na+ channels inactivate. Thus, w<span>ithout Na+ channels, neurons would not be able to depolarize and consequently, the action potential would not be generated.
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6 0
3 years ago
When a lion and a tiger mate, they have
atroni [7]

A postzygotic barrier is the sort of reproductive barrier that prevents the hybrids from reproducing after a lion and a tiger mate and create offspring.

<h3>What does the biological term replicate mean?</h3>

Reproduction is the process of producing descendants. The two basic types of reproduction are sexual and asexual. A sexually reproducing organism is genetically different and has the genetic information of both of its mothers. Genetically identical children are produced through asexual reproduction by having each parent repeat itself.

<h3>What is the name of the reproductive process?</h3>

Reproduction is the process by which new individual creatures, or "offspring," are produced from the "parent" or "parents" (or procreation or breeding). Reproduction is a fundamental element of all known life, and it is the reason that every single organism exists.

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6 0
1 year ago
7. Pyrethrums are chemicals used to kill insects. In bed bugs, the mutant-type allele, r, confers resistance, but only in homozy
natita [175]

Answer:

Allele frequency

Normal allele  = 0.9

Mutant r allele = 0.1

Genotype frequency

Homozygous normal bugs = 0.81

Homozygous mutant bug = 0.01

Heterozygous normal bug with one mutant r allele and one normal allele = 0.18

Explanation:

It is given that 99% of the bugs were killed after the spray of  pyrethrum. This suggests that 1% of the bugs that were not killed must be homozygous for the mutant type allele "r"

Thus, the frequency of homozygous "rr" species i.e q^2 = 0.01

From this we can evaluate the frequency of mutant "r" allele.

Thus, q = \sqrt{0.01} \\

q = 0.1

As per Hardy-Weinberg first equilibrium equation, p + q = 1

Substituting the value of q in above equation, we get

p = 1 - q\\p = 1 - 0.1\\p = 0.9

Thus, the frequency of homozygous normal bug is equal to

p^2 = 0.9^2 = 0.81

As per Hardy-Weinberg second equilibrium equation-

p^2 + q^2 + 2pq = 1\\

Substituting all the available values we get -

0.81 + 0.01+ 2pq = 1\\2pq = 0.18

Allele frequency

Normal allele  = 0.9

Mutant r allele = 0.1

Genotype frequency

Homozygous normal bugs = 0.81

Homozygous mutant bug = 0.01

Heterozygous normal bug with one mutant r allele and one normal allele = 0.18

3 0
3 years ago
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