3 years ago

i'll give brainliest!!! what is the width of a rectangle that has an area of 96 square inches and a length of 12 inches?

Mathematics

1 answer:

Nata [24]3 years ago

7 0

Answer:

it's 8 inches luvvvv

Step-by-step explanation:

hope this helps

You might be interested in

5q + 5/14 + 8z + 2/14 + 4q - 4z

SVEN [57.7K]

Answer:

9q+4z+12

Step-by-step explanation:

7 0

3 years ago

triangle ABC has A(1,2), B(3,1), and C(2,4). it is reflected across the x-axis and then across the y-axis. which point is in the

jarptica [38.1K]

What subject is this if this is math I am good at it

7 0

3 years ago

Meryl spend a total of 68.82 for 2 pairs of sneakers with the same cost . The sale tax is 5.32 . Meryl also use a coupon for 3.0

Nimfa-mama [501]

$68.82
$68.82 - $5.32
$63.50 - $3.00
$60.50 / 2
$30.25 each pair of shoes

8 0

4 years ago

Read 2 more answers

The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.

slamgirl [31]

Answer:

$b=-6\\c=7$

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

$y=a(x-x_1)(x-x_2)$

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

$a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}$

substitute

$y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))$

Applying the distributive property convert to expanded form

$y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})$

$y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)$

$y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7$

$y=x^2-6x+7$

therefore

$b=-6\\c=7$

7 0

3 years ago

What the answer to this problem

Lana71 [14]

The Answer Would Be The Second Bubble. The Quotient is 6 with a remainder of 3.

Hope I Helped :)

8 0

3 years ago