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ivolga24 [154]
2 years ago
6

PLZ HELP What is the best approximation of the solution to the system to the nearest integer values? (2, 3) (1, 3) (3, 4) (3, 2)

Graph of a system of linear equations. Equation 1 is 5x plus 2y equals 16. Equation 2 is x plus 3y equals 12.

Mathematics
2 answers:
Kruka [31]2 years ago
8 0

Answer:

  (2, 3)

Step-by-step explanation:

The point with integer coordinates nearest the solution point seems to be (2, 3).

defon2 years ago
3 0

I have done the test :)

Hope it helped

<h2>PLEASE MARK BRAINIEST</h2>

Answer: (PIC)

(2,3)

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Answer:

4 1/2. Root 18 simplifies to 4.242640687, which is less than 4.50

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Learning Thoery In a learning theory project, the proportion P of correct responses after n trials can be modeled by p = 0.83/(1
elena-s [515]

Answer:

a)P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536

b) P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666

c) 0.75 =\frac{0.83}{1+e^{-0.2n}}

1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}

e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}

ln e^{-0.2n} = ln (\frac{8}{75})

-0.2 n = ln(\frac{8}{75})

And then if we solve for t we got:

n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials

d) If we find the limit when n tend to infinity for the function we have this:

lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

Step-by-step explanation:

For this case we have the following expression for the proportion of correct responses after n trials:

P(n) = \frac{0.83}{1+e^{-0.2t}}

Part a

For this case we just need to replace the value of n=3 in order to see what we got:

P(n=3) = \frac{0.83}{1+e^{-0.2(3)}}= \frac{0.83}{1+ e^{-0.6}} = 0.536

So the number of correct reponses  after 3 trials is approximately 0.536.

Part b

For this case we just need to replace the value of n=7 in order to see what we got:

P(n=7) = \frac{0.83}{1+e^{-0.2(7)}}= \frac{0.83}{1+ e^{-1.4}} = 0.666

So the number of correct responses after 7 weeks is approximately 0.666.

Part c

For this case we want to solve the following equation:

0.75 =\frac{0.83}{1+e^{-0.2n}}

And we can rewrite this expression like this:

1+ e^{-0.2n} = \frac{0.83}{0.75}= \frac{83}{75}

e^{-0.2n} = \frac{83}{75}-1= \frac{8}{75}

Now we can apply natural log on both sides and we got:

ln e^{-0.2n} = ln (\frac{8}{75})

-0.2 n = ln(\frac{8}{75})

And then if we solve for t we got:

n = \frac{ln(\frac{8}{75})}{-0.2} = 11.19 trials

And we can see this on the plot attached.

Part d

If we find the limit when n tend to infinity for the function we have this:

lim_{n \to \infty} \frac{0.83}{1+e^{-0.2t}} = 0.83

So then the number of correct responses have a limit and is 0.83 as n increases without bound.

5 0
2 years ago
Pls help pls help me<br><br><br><br><br><br> Compare the following 2/-3, -4/5, 21/-32, -15/24
mote1985 [20]

Step-by-step explanation:

to compare them, we should all bring to the same denominator.

the lcm (lowest common multiplier) is the that denominator.

let's use the approach of the prime factors :

3 : 3

5 : 5

32 : 2×2×2×2×2

24 : 2×2×2×3

the lcm is the combination of the longest "streaks" of the prime factors.

so,

2×2×2×2×2 × 3 × 5 = 32×15 = 480

2/-3 = -2/3 = -320/480 (as 3×160 = 480)

-4/5 = -4×96 / 5×96 = -384/480 (as 5×96 = 480)

21/-32 = -21/32 = -315/480 (as 32×15 = 480)

-15/24 = -15×20 / 24×20 = -300/480 (24×20 = 480)

as

-384/480 < -320/480 < -315/480 < -300/480

we can say

-4/5 < -2/3 < -21/32 < -15/24

3 0
2 years ago
What would the answer be?
Alexus [3.1K]
C.) 27 and a half. 12 minutes times 5 equals an hour so 5 and a half pages times 5 equals 27 and a half pages per hour.
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3 years ago
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