Answer:
an = n -27
Step-by-step explanation:
The general term (an) of an arithmetic sequence is given by the formula ...
an = a1 + d(n -1)
where a1 is the first term and d is the common difference.
Your sequence has a first term of a1 = -26 and a common difference of d = 1. Putting these values into the formula gives ...
an = -26 + 1(n -1)
This can be simplified to ...
an = n - 27
Given: lines l and m are parallel, and line t is a transversal.
angle pair result/justification
1 and 2 are equal (vertical angles)
6 and 8 are equal (corresponding angles)
1 and 4 are equal (alternate exterior angles)
4 and 8 are supplementary angles (i.e. add up to 180 degrees, a straight angle)
Note:
alternate angles are on opposite sides of the transversal, and each attached to a different (parallel) line.
If they are both enclosed by the parallel lines, they are alternate interior angles (examples: angles 2 and 3, 6 and 7)
If they are both outside of the two parallel lines, they are alternate exterior angles (examples: angles 1 and 4, 5 and 8)
1) <span>-3, 6, -9, 12...
f(2) = -2*6 - (-3) = -9
f(3) = -2*-9 - (6) = 12
2) </span><span>2) Choose the slope-intercept equation of the line that passes through the point (-2, 2) and is parallel to y = 4x + 7.
Slope equals 4, since it's parallel. Substituting...
2 = 4*-2 + b Add 8 to both sides
10 = b
y= 4x + 10
3)Question is poorly transcribed, but assuming the points are (10, 60) and (16, 96):
Average rate of change = (96-60) / (16-10) = 36 / 6 = 6m/s.
4) A slope of zero means that y does not change with x. This means y is the same for any x value, so y is a horizontal line.
The third graph, the one where y= -6, is the correct answer.
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Answer:
Step-by-step explanation:
Use the formula 
(distance is equal to rate/speed multiplied by time) to solve this problem.
We know that one minute is equal to 60 seconds. Therefore, the distance travelled by the cat in 1 minute is equal to 
.
To catch the cat, the dog needs to also cover an additional 48 meters, because the cat was initially 48 meters away from the dog and it ran away from the dog. Hence, the dog will need to cover 
meters in one minute.
Therefore, we have:
