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Firdavs [7]
3 years ago
6

If 4 is 1/4 what is the whole

Mathematics
2 answers:
vredina [299]3 years ago
6 0

Answer:

Step-by-step explanation:

23

nevsk [136]3 years ago
5 0

Answer:16/1

Step-by-step explanation:

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What is the slope of a line that is perpendicular to the line whose equation is 2y = 3x - 1?
alexandr1967 [171]

Answer:

The slope of the line is -\frac{2}{3}

Step-by-step explanation:

For any line y=mx+b, a line that is perpendicular to it is y_\perp =-\frac{1}{m} x+b.

Therefore the slope of the perpendicular line is -\frac{1}{m}.

For our case y=\frac{3}{2}x-\frac{1}{2} therefore the slope of the prependicular is the reciprocal of \frac{3}{2} multiplied by -1.

\therefore\:slope=-\frac{2}{3}.

4 0
3 years ago
Which phrase matches the algebraic expression below 2(x-7)+10
Alekssandra [29.7K]

Answer:

The sum of a number and 7 multiplied by 2 is increased by 10

Step-by-step explanation:

8 0
3 years ago
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What is the graph of the equation 4x-5y=15
pantera1 [17]
Hello James!

Graph using the slope and y - intercept.
Slope: \frac{4}{5}
Y-intercept: -3

The graph looks like this ↓↓↓

6 0
3 years ago
Read 2 more answers
In the illustration below, the three cube-shaped tanks are identical. The spheres in any given tank
fredd [130]

Answer:

1) Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) Amount \ of \, water \ remaining \ in \, the \ tank \ is \  \frac{x^3(6-\pi) }{6}

Step-by-step explanation:

1) Here we have;

First tank A

Volume of tank = x³

The  volume of the sphere = \frac{4}{3} \pi r^3

However, the diameter of the sphere = x therefore;

r = x/2 and the volume of the sphere is thus;

volume of the sphere = \frac{4}{3} \pi \frac{x^3}{8}= \frac{1}{6} \pi x^3

For tank B

Volume of tank = x³

The  volume of the spheres = 8 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 2·D = x therefore;

r = x/4 and the volume of the sphere is thus;

volume of the spheres = 8 \times \frac{4}{3} \pi (\frac{x}{4})^3= \frac{x^3 \times \pi }{6}

For tank C

Volume of tank = x³

The  volume of the spheres = 64 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 4·D = x therefore;

r = x/8 and the volume of the sphere is thus;

volume of the spheres = 64 \times \frac{4}{3} \pi (\frac{x}{8})^3= \frac{x^3 \times \pi }{6}

Volume occupied by the spheres are equal therefore the three tanks contains the same volume of water

2) For the 4th tank, we have;

number of spheres on side of the tank, n is given thus;

n³ = 512

∴ n = ∛512 = 8

Hence we have;

Volume of tank = x³

The  volume of the spheres = 512 \times \frac{4}{3} \pi r^3

However, the diameter of the spheres 8·D = x therefore;

r = x/16 and the volume of the sphere is thus;

volume of the spheres = 512\times \frac{4}{3} \pi (\frac{x}{16})^3= \frac{x^3 \times \pi }{6}

Amount of water remaining in the tank is given by the following expression;

Amount of water remaining in the tank = Volume of tank - volume of spheres

Amount of water remaining in the tank = x^3 - \frac{x^3 \times \pi }{6} = \frac{x^3(6-\pi) }{6}

Amount \ of \ water \, remaining \, in \, the \ tank =  \frac{x^3(6-\pi) }{6}.

5 0
3 years ago
Help please?
Nikolay [14]

Answer:

An angle bisector.

Step-by-step explanation:

This is a ray (Line that extends only one infinitely while the other way has an eventual and perceivable end) that divides an angle (in this case, the angle of a triangle) into two equal parts.

7 0
3 years ago
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