Step 1: Insert 2.6 hours for the variable of time and solve.
70.443 + 4.885(2.6)
70.443+ 12.701
= 83.144
This is Ann's EXPECTED exam score. Because of the concert, Ann scored 16 points lower than this number.
Step 2: Subtract 16 from Ann's expected score.
83.144 - 16
= 67.144
The answer is going to be D
X > 5
x = 5 is not a solution because x is always greater than 5.
6.5 is the mean of the data
The height attained by the arrow is modelled as,

Given that the initial height is 20 ft and the initial velocity is 179 ft per second,

Substitute the values,

When the arrow hits the ground its height will become zero,

Applying the quadratic formula,
![\begin{gathered} t=\frac{-(-179)\pm\sqrt[]{(-179)^2-4(-16)(20)}}{2(-16)} \\ t=\frac{179\pm\sqrt[]{33321}}{-32} \\ t=\frac{179\pm182.54}{-32} \\ t=\frac{179+182.54}{-32},t=\frac{179-182.54}{-32} \\ t=-11.298,t=0.1106 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20t%3D%5Cfrac%7B-%28-179%29%5Cpm%5Csqrt%5B%5D%7B%28-179%29%5E2-4%28-16%29%2820%29%7D%7D%7B2%28-16%29%7D%20%5C%5C%20t%3D%5Cfrac%7B179%5Cpm%5Csqrt%5B%5D%7B33321%7D%7D%7B-32%7D%20%5C%5C%20t%3D%5Cfrac%7B179%5Cpm182.54%7D%7B-32%7D%20%5C%5C%20t%3D%5Cfrac%7B179%2B182.54%7D%7B-32%7D%2Ct%3D%5Cfrac%7B179-182.54%7D%7B-32%7D%20%5C%5C%20t%3D-11.298%2Ct%3D0.1106%20%5Cend%7Bgathered%7D)
Since time cannot be negative, we have to neglect the negative value.
Thus, it can be concluded that the arrow will hit the ground after 0.1106 seconds approximately.