Cute one!
<span>
</span>Summarizing:
<span>sec(acot(tan(asin(sin(pi/3)))) .... use asin(sin(x))=x
</span>=sec(acot(tan(pi/3)))
=sec(acot(sqrt(3))) ......... use acot(x)=atan(1/x)
=sec(atan(1/sqrt(3)))
=sec(atan(sqrt(3)/3)) .... evaluate atan(sqrt(3)/3), use unit circle
=sec(pi/6)
=1/cos(pi/6)...... evaluate cos(pi/6), use unit circle
=1/(sqrt(3)/2)
=2/sqrt(3) .... now rationalize
=2sqrt(3)/3
Answer: The Athletic can other 12 volleyballs.
Step-by-step explanation:
If the director has $277 to spend then it means The director can spend at most $277.
Now one volleyball cost $22 and so we could represent the number of volleyballs you can buy by the expression 22x and including the shipping fee,we will extend the expression to 22x + 13 Now since the Director can spend up to $277 or less we can write the whole situation in a form of inequality as,
22x + 13 ≤ 277 Now solve for x to determine the number of volleyballs
-13 -13
22x 
264
x 12
Answer:
B. 34%.
Step-by-step explanation:
94 - 78 = 16 which is 2 times the standard deviation from the mean.
For a normal distribution this is 34% of the total students.
You multiply the 2 values together and B is the correct answer
Step-by-step explanation:
the extreme values (minimum, maximum) of a function are the zero points of the first derivation of the function.
so,
f'(x) = 2x + b
and then
2x + b = 0
we know, x = 20 for the minimum
2×20 + b = 0
40 + b = 0
b = -40
therefore, the actual function is
f(x) = x² - 40x + 164
the target format is
f(x) = (x - h)² + k = x² - 2hx + h² + k
so,
-40x = -2hx
-40 = -2h
h = 20
and
h² + k = 164
20² + k = 164
400 + k = 164
k = -236
