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slamgirl [31]
2 years ago
9

Find an expression which represents the sum of (7x - 8y) and (-6x - 6y) in simplest terms.

Mathematics
1 answer:
grigory [225]2 years ago
3 0

Answer:

\displaystyle (7x - 8y) + (-6x - 6y) = x - 14y

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle (7x - 8y) + (-6x - 6y)<em />

<em />

<u>Step 2: Simplify</u>

  1. Combine like terms (x):                                                                                    \displaystyle (7x - 8y) + (-6x - 6y) = x - 8y - 6y
  2. Combine like terms (y):                                                                                    \displaystyle (7x - 8y) + (-6x - 6y) = x - 14y
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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If the equations 2x +y =7 and x-y=2are solved simultaneously, then y=_________​
alisha [4.7K]

Answer:

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Step-by-step explanation:

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(b) A line has the equation y = 6x + 11
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Hi, to begin, the ordered pair value (-3, 15) has an x-value of -3. So, to see if it lies on the line of your equation y = 6x + 11, plug -3 in for x. This gives you y = 6(-3) + 11 = -7 So the ordered pair answer for this would be (-3, -7) and not (-3, 15). So the answer is no.

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Read 2 more answers
Given r(x) = startfraction 11 over (x minus 4) squared endfraction , which represents a domain restriction on r(x) and the corre
Dmitry_Shevchenko [17]

The domain and inverse of the function

r(x) = \frac{11}{(x - 4)^2} is

Domain = \mathbb{R} - \{4\},

r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4

What is a function?

A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.

There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.

The given function is

r(x) = \frac{11}{(x - 4)^2}

r(x) is not defined if x - 4 = 0

r(x) is not defined for x = 4

Domain = \mathbb{R} - \{4\},

Where \mathbb{R} is the set of all real number

Let r(x) = y

\frac{11}{(x-4)^2} = y\\(x - 4)^2 = \frac{11}{y}\\x - 4 = \pm \sqrt{\frac{11}{y}}\\x = \pm\sqrt{\frac{11}{y}}  +4

<em />r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4

To learn more about function, refer to the link:

brainly.com/question/22340031

#SPJ4

3 0
10 months ago
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