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2 years ago

Find an expression which represents the sum of (7x - 8y) and (-6x - 6y) in simplest terms.

Mathematics

1 answer:

grigory [225]2 years ago

3 0

Answer:

$\displaystyle (7x - 8y) + (-6x - 6y) = x - 14y$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle (7x - 8y) + (-6x - 6y)$

Step 2: Simplify

Combine like terms (x): $\displaystyle (7x - 8y) + (-6x - 6y) = x - 8y - 6y$
Combine like terms (y): $\displaystyle (7x - 8y) + (-6x - 6y) = x - 14y$

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2 years ago

If the equations 2x +y =7 and x-y=2are solved simultaneously, then y=_________

alisha [4.7K]

Answer:

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2 years ago

(b) A line has the equation y = 6x + 11

marin [14]

Hi, to begin, the ordered pair value (-3, 15) has an x-value of -3. So, to see if it lies on the line of your equation y = 6x + 11, plug -3 in for x. This gives you y = 6(-3) + 11 = -7 So the ordered pair answer for this would be (-3, -7) and not (-3, 15). So the answer is no.

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2 years ago

Read 2 more answers

Given r(x) = startfraction 11 over (x minus 4) squared endfraction , which represents a domain restriction on r(x) and the corre

Dmitry_Shevchenko [17]

The domain and inverse of the function

$r(x) = \frac{11}{(x - 4)^2}$ is

Domain = $\mathbb{R} - \{4\}$ ,

$r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4$

What is a function?

A function from A to B is a rule that assigns to each element of A a unique element of B. A is called the domain of the function and B is called the codomain of the function.

There are different operations on functions like addition, subtraction, multiplication, division and composition of functions.

The given function is

$r(x) = \frac{11}{(x - 4)^2}$

r(x) is not defined if x - 4 = 0

r(x) is not defined for x = 4

Domain = $\mathbb{R} - \{4\}$ ,

Where $\mathbb{R}$ is the set of all real number

Let r(x) = y

$\frac{11}{(x-4)^2} = y\\(x - 4)^2 = \frac{11}{y}\\x - 4 = \pm \sqrt{\frac{11}{y}}\\x = \pm\sqrt{\frac{11}{y}} +4$

$r^{-1}(x) = \pm \sqrt{\frac{11}{x}} + 4$

To learn more about function, refer to the link:

brainly.com/question/22340031

#SPJ4

3 0

10 months ago