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2 years ago

Write the quadratic equation in standard form: 4x2 – 20 = -6x

Mathematics

2 answers:

timofeeve [1]2 years ago

8 0

Answer:

4x^2+6x-20=0

Step-by-step explanation:

MissTica2 years ago

4 0

Im really bad at math but i like i think this is right, im trying to help lol

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Find p(2) and p(4) for the function p(x) = 6x4 + 4x3 – 3x2 + 8x + 15.

gulaghasi [49]

Answer:

p(2) =147 and p(4) = 1791

Step-by-step explanation:

We are given p(x)= 6x^4 + 4x^3 – 3x^2 + 8x + 15.

Now we need to find value of p(2) and p(4)

Put x =2,

p(2) = 6(2)^4 + 4(2)^3 – 3(2)^2 + 8(2) + 15

p(2) = 6(16)+4(8)-3(4)+8(2)+15

p(2) = 96+32-12+16+15

p(2) = 147

Now put x = 4

p(4) = 6(4)^4 + 4(4)^3 – 3(4)^2 + 8(4) + 15

p(4) = 6(256)+4(64)-3(16)+8(4)+15

p(4) = 1536+256-48+32+15

p(4) = 1791

3 0

3 years ago

Read 2 more answers

Lenny sold 576 tacos in 48 hours what was lenny's average rate of tacos sales

cupoosta [38]

If your looking for hourly they sold a total of 12 tacos per hour.
If your looking for daily they sold a total of 288 tacos per day.

4 0

3 years ago

Read 2 more answers

For each value of y , determine whether it is a solution to -21=6y-9 . A -5, B 3 , C -2, D 9

Nezavi [6.7K]

Option C

For each value of y, -2 is a solution of -21 = 6y - 9

Solution:

Given, equation is – 21 = 6y – 9

We have to find that whether given set of options can satisfy the above equation or not

Now, let us check one by one option

Option A)

Given option is -5

Let us substitute -5 in given equation

- 21 = 6(-5) – 9

- 21 = -30 – 9

- 21 = - 39

L.H.S ≠ R.H.S ⇒ not a solution

Option B)

Given option is 3

- 21 = 6(3) – 9

- 21 = 18 – 9

- 21 = 9

L.H.S ≠ R.H.S ⇒ not a solution

Option C)

Given option is -2

- 21 = 6(-2) – 9

- 21 = - 12 – 9

- 21 = - 21

L.H.S = R.H.S ⇒ yes a solution

Option D)

- 21 = 6(9) – 9

- 21 = 54 – 9

- 21 = 45

L.H.S ≠ R.H.S ⇒ not a solution

Hence, the solution for the given equation is – 2, so option c is correct

6 0

3 years ago

What is the measure of a

Softa [21]

70º

It's a supplementary angle so 180º - 110º

3 0

2 years ago

Read 2 more answers

Plsss help no one answered the other times I put this question

svetlana [45]

Answer:

a) The equation (10s + 8w) represents the calories Bridget ate on Monday and the equation (20s + w) represents the calories she ate the next day.

b) The number of calories in each strawberry is 4 and the number of calories in each vanilla wafer cookie is 19. The solution is s= 4 and w = 19.

Step-by-step explanation:

For part A, Bridget ate 10 strawberries and 8 vanilla wafer cookies on Monday. Since the the number of calories in a strawberry is s and the number of calories in a vanilla wafer cookie is w , the number of calories Bridget ate on Monday is 10s + 8w. The next day, Bridget ate 20 strawberries and 1 vanilla wafer cookie. Hence, the number of calories Bridget ate on the next day is 20s + w.

For part B,

we will create two different simultaneous equations.

Equation 1: 10s + 8w = 192

Equation 2: 20s + w = 99

We need to find one of the terms first to solve the other term. For this case, I will solve for w first.

Multiply the first equation by 2.

Equation 3: 20s + 16w = 192*2 = 384.

Now, subtract equation 2 from this new equation.

Equation 4:

(20s + 16w) - (20s + w) = 384 - 99

20s + 16w - 20s - w = 285

15w = 285

This leaves only w left and we can solve w.

w = 285 / 15 = 19

Now, we can solve for s using equation 2.

20s + 19 = 99

20s = 99-19 = 80

Hence,

s = 80/20 = 4

7 0

3 years ago