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3 years ago

√ 32 +√ 48/√ 8 +√ 12

Mathematics

1 answer:

g100num [7]3 years ago

4 0

Answer:

Please refer to the photo

I don't know which one you want

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Please help don’t ignore !!

sladkih [1.3K]

X^2+3x+1+4x-1+2x^2
Combine like terms:
x^2+2x^2=3x^2
3x+4x=7x
1+(-1)=0
Solution:
3x^2+7x
All you can do here is simplify it

5 0

3 years ago

PLS HELP What is the area, in square of the parallelogram below?

Arlecino [84]

Answer:

35 square units

Step-by-step explanation:

Area of the parallelogram = 7*5 = 35 square units

6 0

3 years ago

Solve for y. y-260=-11/5*(x-60)

Otrada [13]

its -325

hope this helped gooooood luck ;3

7 0

4 years ago

Select the smallest fraction from the following fractions. 2/4 3/6 1/3 7/9

enot [183]

Answer:

it 1/3

Step-by-step explanation:

2/4 is just 1/2, 3/6 is also 1/2, 7/9 is over 1/2 and 1/3 is the only one less then 1/2 so it's the lowest fraction. This is not the proper way to solve it but it works and it's faster

3 0

4 years ago

Read 2 more answers

Find the volume of a right circular cone that has a height of 10.7 in and a base with a diameter of 8.1 in. Round your answer to

scoundrel [369]

Answer:

$V = \pi r^2 h$

And for this case the value for the height is $h = 10.7 in$ the diameter is provided $D = 2r = 8.1 in$ so then the radius is given by:

$r = \frac{D}{2}=\frac{8.1 in}{2}= 4.05 in$

Then we can find the volume with the first formula and replacing we got:

$V = \pi (4.05in)^2 (10.7 in)= 551.4 in ^3$

The final answer for this case would be 551.4 cubic inches

Step-by-step explanation:

The volume for a right circular cone is given by this formula:

$V = \pi r^2 h$

And for this case the value for the height is $h = 10.7 in$ the diameter is provided $D = 2r = 8.1 in$ so then the radius is given by:

$r = \frac{D}{2}=\frac{8.1 in}{2}= 4.05 in$

Then we can find the volume with the first formula and replacing we got:

$V = \pi (4.05in)^2 (10.7 in)= 551.4 in ^3$

The final answer for this case would be 551.4 cubic inches

7 0

3 years ago

Read 2 more answers