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Eddi Din [679]
3 years ago
11

Find the volume of a right circular cone that has a height of 10.7 in and a base with a diameter of 8.1 in. Round your answer to

the nearest tenth of a cubic inch.
Mathematics
2 answers:
scoundrel [369]3 years ago
7 0

Answer:

V = \pi r^2 h

And for this case the value for the height is h = 10.7 in the diameter is provided D = 2r = 8.1 in so then the radius is given by:

r = \frac{D}{2}=\frac{8.1 in}{2}= 4.05 in

Then we can find the volume with the first formula and replacing we got:

V = \pi (4.05in)^2 (10.7 in)= 551.4 in ^3

The final answer for this case would be 551.4 cubic inches

Step-by-step explanation:

The volume for a right circular cone is given by this formula:

V = \pi r^2 h

And for this case the value for the height is h = 10.7 in the diameter is provided D = 2r = 8.1 in so then the radius is given by:

r = \frac{D}{2}=\frac{8.1 in}{2}= 4.05 in

Then we can find the volume with the first formula and replacing we got:

V = \pi (4.05in)^2 (10.7 in)= 551.4 in ^3

The final answer for this case would be 551.4 cubic inches

Svetlanka [38]3 years ago
6 0

Answer V:183.8^3 previous answer is wrong

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Ricardo and Tammy practice putting golf balls. Ricardo makes 47% of his putts and Tammy makes 51% of her putts. Suppose that Ric
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Answer:

0.3821 = 38.21% probability that Ricardo makes a higher proportion of putts than Tammy.

Step-by-step explanation:

To solve this question, we need to understand the normal distribution, the central limit theorem, and subtraction of normal variables.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

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Ricardo makes 47% of his putts, and attempts 25 putts.

By the Central Limit Theorem, we have that:

\mu_R = 0.47, s_R = \sqrt{\frac{0.47*0.53}{25}} = 0.0998

Tammy makes 51% of her putts, and attempts 30 putts.

By the Central Limit Theorem, we have that:

\mu_T = 0.51, s_T = \sqrt{\frac{0.51*0.49}{30}} = 0.0913

What is the probability that Ricardo makes a higher proportion of putts than Tammy?

This is the probability that the subtraction of R by T is larger than 0. The mean and standard deviation of this distribution are, respectively:

\mu = \mu_R - \mu_T = 0.47 - 0.51 = -0.04

s = \sqrt{s_R^2 + s_T^2} = \sqrt{0.0998^2 + 0.0913^2} = 0.1353

This probability is 1 subtracted by the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0 - (-0.04)}{0.1353}

Z = 0.3

Z = 0.3 has a pvalue of 0.6179

1 - 0.6179 = 0.3821

0.3821 = 38.21% probability that Ricardo makes a higher proportion of putts than Tammy.

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