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3 years ago

PLS HELP What is the area, in square of the parallelogram below?

Mathematics

1 answer:

Arlecino [84]3 years ago

6 0

Answer:

35 square units

Step-by-step explanation:

Area of the parallelogram = 7*5 = 35 square units

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Can someone please help me??

dmitriy555 [2]

Answer:

I is clear that, the linear equation $5x+12=5x-7$ has no solution.

Step-by-step explanation:

Checking the first option:

$\frac{2}{3}\left(9x+6\right)=6x+4$

$6x+4=6x+4$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$6x+4-4=6x+4-4$

$6x=6x$

$\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}$

$6x-6x=6x-6x$

$0=0$

$\mathrm{Both\:sides\:are\:equal}$

$\mathrm{True\:for\:all}\:x$

Checking the 2nd option:

$5x+12=5x-7$

$\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}$

$5x+12-5x=5x-7-5x$

$\mathrm{Simplify}$

$12=-7$

$\mathrm{The\:sides\:are\:not\:equal}$

$\mathrm{No\:Solution}$

Checking the 3rd option:

$4x+7=3x+7$

$\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}$

$4x+7-7=3x+7-7$

$\mathrm{Simplify}$

$4x=3x$

$\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}$

$4x-3x=3x-3x$

$\mathrm{Simplify}$

$x=0$

Checking the 4th option:

$-3\left(2x-5\right)=15-6x$

$\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}$

$-6x+15-15=15-6x-15$

$\mathrm{Simplify}\$

$-6x=-6x$

$\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}$

$-6x+6x=-6x+6x$

$\mathrm{Simplify}$

$\mathrm{Both\:sides\:are\:equal}$

$\mathrm{True\:for\:all}\:x$

Result:

Therefore, from the above calculations it is clear that, the linear equation

$5x+12=5x-7$ has no solution.

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3 years ago

At a drag race, the light turns green and 0.00125 hours later, a dragster is traveling 300 miles per hour. Calculate the acceler

taurus [48]

The acceleration is 98ft/s ²
Hope I helped!

8 0

3 years ago

A. Find 33 and a third % of 879

Anvisha [2.4K]

Answer:

Step-by-step explanation:

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3 years ago

Please help ASAP !!!!!

shusha [124]

Answer:

Step-by-step explanation:

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3 years ago

Hat is the solution to the equation 3/3(4c + 16)=2c+9 ? c =

marusya05 [52]

If it is $\frac{3}{3(4c+16)}$ =2c+9, go to AAAAAA
if it is ( $\frac{3}{3}$ )(4c+16)=2c+9, go to BBBBB

AAAAAAAAA
$\frac{3}{3(4c+16)}$ =2c+9
$\frac{1}{4c+16}$ =2c+9
times 4c+16 to both sides
1=(2c+9)(4c+16)
distribute
1=8c^2+68c+144
minus 1 both sides
0=8c^2+68c+143
use quadratic formula
c= $\frac{-17- \sqrt{3} }{4}$ or $\frac{-17+ \sqrt{3} }{4}$

BBBBBBBBBBBB
(3/3)(4c+16)=2c+9
1(4c+16)=2c+9
4c+16=2c+9
minus 2c both sides
2c+16=9
minus 16 both sides
2c=-7
divide both sides by 2
c=-7/2
c=-3.5

if it is $\frac{3}{3(4c+16)}$ =2c+9,
c= $\frac{-17- \sqrt{3} }{4}$ or $\frac{-17+ \sqrt{3} }{4}$

if it is ( $\frac{3}{3}$ )(4c+16)=2c+9, c=-3.5

7 0

3 years ago

Read 2 more answers