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ElenaW [278]
3 years ago
6

Which kinds of symmetry does a square have?

Mathematics
1 answer:
spin [16.1K]3 years ago
4 0
Vertical symmetry because you can cut a square in half vertically and the two parts be exactly the same. Horizontal symmetry because you can cut a square in half horizontally and the two parts be exactly the same. Diagonal symmetry because you can cut the square from corner to corner and the two parts look exactly the same. Rotational symmetry because you can rotate the square and it still look exactly the same. So a square has all of those symmetries. I hope this helped!
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The 59th and 4th team of an Ap are - 61 and 64 respectively. Show that the common differences is - 2.5 and 23rd term is 16.5​
Mnenie [13.5K]

Answer:

See answers below

Step-by-step explanation:

T59 = a+58d = -61

T4 = a+3d = 64.

Subtract

58d-3d = -61-64

-55d = -125

d =125/55

d = 25/11

Get a;

From 2

a+3d = 64

a+3(25/11) = 64

a = 64-75/11

a = 704-75/11

a = 629/11

T23 = a+22d

T23 = 629/11+22(25/11)

T23 = 1179/11

3 0
3 years ago
DESPERATELY NEED HELP ON THIS QUESTION
Triss [41]
Angle aed has to be 80 since the two triangles share two of the same angles

5 0
3 years ago
HELP- PLS SOMEONE HELP ME SOB
BlackZzzverrR [31]

Answer:

150 degrees

Step-by-step explanation:

Use the equation below to find the sum of all the interior angles in this polygon:

(number of sides - 2)*180

number of sides = 6

(6-2)*(180) = 4*(180) = 720

Now that you know the total sum, subtract all other angles to find x:

720 - 90 - 162 - 101 - 96 - 121 = 150

5 0
2 years ago
A study indicates that 37% of students have laptops. You randomly sample 30 students. Find the mean and the standard deviation o
Brilliant_brown [7]

Answer:

The mean and the standard deviation of the number of students with laptops are 1.11 and 0.836 respectively.

Step-by-step explanation:

Let <em>X</em> = number of students who have laptops.

The probability of a student having a laptop is, P (X) = <em>p</em> = 0.37.

A random sample of <em>n</em> = 30 students is selected.

The event of a student having a laptop is independent of the other students.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The mean and standard deviation of a binomial random variable <em>X</em> are:

\mu=np\\\sigma=\sqrt{np(1-p)}

Compute the mean of the random variable <em>X</em> as follows:

\mu=np=30\times0.37=1.11

The mean of the random variable <em>X</em> is 1.11.

Compute the standard deviation of the random variable <em>X</em> as follows:

\sigma=\sqrt{np(1-p)}=\sqrt{30\times0.37\times(1-0.37)}=\sqrt{0.6993}=0.836

The standard deviation of the random variable <em>X</em> is 0.836.

5 0
3 years ago
Sue drank 2/5 of her water bottle and sally drank 4/10 of her water bottle how much water did both girls drank?
stealth61 [152]

well, clearly the LCD from the denominators of 5 and 10 is just 10, thus

\bf \stackrel{\textit{Sue}}{\cfrac{2}{5}}+\stackrel{\textit{Sally}}{\cfrac{4}{10}}\implies \stackrel{\textit{LCD of 10}}{\cfrac{(2)2~~+~~(1)4}{10}}\implies \cfrac{2+4}{10}\implies \cfrac{6}{10}\implies \stackrel{\textit{simplified}}{\cfrac{3}{5}}

3 0
3 years ago
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