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yuradex [85]
3 years ago
15

I need help with the first one please someone help I don’t get it!

Mathematics
1 answer:
levacccp [35]3 years ago
3 0

Answer:

2.2

Step-by-step explanation:

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What is the coefficient of x2 in the expansion of (x + 2)3?
wolverine [178]
One way is that you can just factor it out: (x+2)(x+2)(x+2)
For the first pair, you get x^2+4x+4.
Then do (x^2+4x+4)*(x+2)
That will be x^3+6x^2+12x+8
So the answer is 6
4 0
3 years ago
(05.01) Which statement best describes the area of the triangle shown below?​
alukav5142 [94]

Answer:

A

Step-by-step explanation:

Area of a triangle:

A=\frac{b*h}{2}

In our case:

b=4

h=2

Plug in what we know:

A=\frac{(4)(2)}{2} \\A=4units

Find the matching solution:

A.) it is 1/2 the area of a rectangle of length 4 units and width 2 units

X B.) it is twice the area of a rectangle of length 4 units and width two units

X C.) it is 1/2 the area of a square of side length 4 units

X D.) it is twice the area of a square of side length 4 units

6 0
2 years ago
HELP FOR BRAINLEST!!
Tju [1.3M]

Answer:

I believe D is the correct answer.

Step-by-step explanation:

8 0
2 years ago
Find the multiplicative inverse of 3 − 2i. Verify that your solution is corect by confirming that the product of
leonid [27]

Answer:

\frac{3}{13} + \frac{2i}{13}

Step-by-step explanation:

The multiplicative inverse of a complex number y  is the complex number z such that (y)(z) = 1

So for this problem we need to find a number z such that

(3 - 2i) ( z ) = 1

If we take z = \frac{1}{3-2i}

We have that

(3- 2i)\frac{1}{3-2i} = 1 would be the multiplicative inverse of 3 - 2i

But remember that 2i = √-2 so we can rationalize the denominator of this complex number

\frac{1}{3-2i } (\frac{3+2i}{3+2i } )=\frac{3+2i}{9-(4i^{2} )} =\frac{3+2i}{9-4(-1)} =\frac{3+2i}{13}

Thus, the multiplicative inverse would be \frac{3}{13} + \frac{2i}{13}

The problem asks us to verify this by multiplying both numbers to see that the answer is 1:

Let's multiplicate this number by 3 - 2i to confirm:

(3-2i)(\frac{3+2i}{13}) = \frac{9-4i^{2} }{13}  =\frac{9-4(-1)}{13}= \frac{9+4}{13} = \frac{13}{13}= 1

Thus, the number we found is indeed the multiplicative inverse of  3 - 2i

4 0
3 years ago
How to regroup to solve the subtraction problem what is the diffrence 316-226=
astra-53 [7]
316-226=90 90 is your answer
5 0
3 years ago
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