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4 years ago

12

What is - 5 = -2 what is the questionwhat is the question

1 answer:

Anni [7]4 years ago

5 0

Answer:

-5 + 3 = -2

Step-by-step explanation:

I don't really understand what you're trying to ask here...

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Which fraction is closest to 1?<br> 5/6, 11/20 or -9/10

ivann1987 [24]

5/6 is closest to 1.

6 0

4 years ago

Read 2 more answers

Evaluate the function f(x) at the given numbers (correct to six decimal places).

Marysya12 [62]

Answer:

$f(2.1) = 0.512195$

$f(2.05) = 0.506173$

$f(2.01)=0.501247$

$f(2.001) = 0.500125$

$f(2.0001) = 0.500012$

$f(1.9) = 0.487179$

$f(1.95) = 0.493671$

$f(1.99) = 0.498747$

$f(1.999) = 0.499875$

$f(1.9999) = 0.499987$

Step-by-step explanation:

Given

$f(x) = \frac{x^2 - 2x}{x^2 - 4}$

Solve for f(x) for all given values of x

First, we need to simplify f(x)

$f(x) = \frac{x^2 - 2x}{x^2 - 4}$

$f(x) = \frac{x(x - 2)}{x^2 - 2^2}$

$f(x) = \frac{x(x - 2)}{(x- 2)(x + 2)}$

$f(x) = \frac{x}{x + 2}$

When $x = 2.1$

$f(x) = \frac{x}{x + 2}$

$f(2.1) = \frac{2.1}{2.1 + 2}$

$f(2.1) = \frac{2.1}{4.1}$

$f(2.1) = 0.512195$

When $x = 2.05$

$f(x) = \frac{x}{x + 2}$

$f(2.05) = \frac{2.05}{2 + 2.05}$

$f(2.05) = \frac{2.05}{4.05}$

$f(2.05) = 0.506173$

When $x = 2.01$

$f(x) = \frac{x}{x + 2}$

$f(2.01)=\frac{2.01}{2.01 +2}$

$f(2.01)=\frac{2.01}{4.01}$

$f(2.01)=0.501247$

When $x = 2.001$

$f(x) = \frac{x}{x + 2}$

$f(2.001) = \frac{2.001}{2.001 +2}$

$f(2.001) = \frac{2.001}{4.001}$

$f(2.001) = 0.500125$

When $x = 2.0001$

$f(x) = \frac{x}{x + 2}$

$f(2.0001) = \frac{2.0001}{2.0001 + 2}$

$f(2.0001) = \frac{2.0001}{4.0001}$

$f(2.0001) = 0.500012$

When $x = 1.9$

$f(x) = \frac{x}{x + 2}$

$f(1.9) = \frac{1.9}{1.9 + 2}$

$f(1.9) = \frac{1.9}{3.9}$

$f(1.9) = 0.487179$

When $x = 1.95$

$f(x) = \frac{x}{x + 2}$

$f(1.95) = \frac{1.95}{1.95 + 2}$

$f(1.95) = \frac{1.95}{3.95}$

$f(1.95) = 0.493671$

When $x = 1.99$

$f(x) = \frac{x}{x + 2}$

$f(1.99) = \frac{1.99}{1.99 + 2}$

$f(1.99) = \frac{1.99}{3.99}$

$f(1.99) = 0.498747$

$f(x) = \frac{x}{x + 2}$

When $x = 1.999$

$f(x) = \frac{x}{x + 2}$

$f(1.999) = \frac{1.999}{1.999 + 2}$

$f(1.999) = \frac{1.999}{3.999}$

$f(1.999) = 0.499875$

When x = 1.9999

$f(x) = \frac{x}{x + 2}$

$f(1.9999) = \frac{1.9999}{1.9999 + 2}$

$f(1.9999) = \frac{1.9999}{3.9999}$

$f(1.9999) = 0.499987$

<em>Note that all values of f(x) are approximated to 6 decimal places</em>

7 0

3 years ago

Which of the following shows the extraneous solution(s) to the logarithmic equation? log4 (x) + log4(x - 3) = log4 (-7x + 21)

Salsk061 [2.6K]

First join the log4 on the left:

log4( x*(x-3) = log4(-7x+21)

Then x = -7, works: -7*(-10)=70 = -7*(-7)+21

x=-3, 18 = 42, does not work

x=3 0=0 works,

However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.

Now x=3 gives log4(0) on the left and right, which does not exist.

So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation

6 0

3 years ago

Read 2 more answers

Hey does anyone know 45 times 62 divided by 12<br><img src="https://tex.z-dn.net/?f=45%20%5Ctimes%2062%20%5Cdiv%2012" id="TexFor

storchak [24]

232.5 would be the answer

5 0

3 years ago

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Giving brainliest to the best answer

lbvjy [14]

Answer:

A

Step-by-step explanation:

7 0

3 years ago

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