<span>x- intercept
</span><span>4x = 20
x = 5
(5,0)
</span>
y- intercept
<span>5y = 20
y = 4
(0,4)
</span>
answer
x- intercept (5,0)
y- intercept (0,4)
Answer:
In total there are 50 students.
Step-by-step explanation:
Since in a group of students 20 study account, 21 study mathematics, 18 study history, 7 study account only, 10 study mathematics only, 6 study account and mathematics only and 3 study mathematics and history only, to determine how many student are there altogether the following calculation must be performed:
7 + 10 + 6 + 3 = 26
Account = 20 - 7 - 6 = 7
Mathematics = 21 - 10 - 6 - 3 = 2
History = 18 - 3 = 15
26 + 7 + 2 + 15 = X
50 = X
Therefore, in total there are 50 students.
Answer:
21 ft by 28 ft
Step-by-step explanation:
To maximize the area, see the attached.
Perimeter will be 4l+3w which is equal to the fencing perimeter, given as 168
4l+3w=168
Making l the subject then
4l=168-3w
l=42-¾w
Area of individual land will be lw and substituting l with l=42-¾w
Then
A=lw=(42-¾w)w=42w-¾w²
A=42w-¾w²
Getting the first derivative of the above with respect to w rhen
42-w6/4=0
w6/4=42
w=42*4/6=28
Since
l=42-¾w=42-¾(28)=21
Therefore, maximum dimensions are 21 for l and 28 for w
Answer:2/3
Step-by-step explanation:
Simplifying
(9m + -6) * 7 = 0
Reorder the terms:
(-6 + 9m) * 7 = 0
Reorder the terms for easier multiplication:
7(-6 + 9m) = 0
(-6 * 7 + 9m * 7) = 0
(-42 + 63m) = 0
Solving
-42 + 63m = 0
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '42' to each side of the equation.
-42 + 42 + 63m = 0 + 42
Combine like terms: -42 + 42 = 0
0 + 63m = 0 + 42
63m = 0 + 42
Combine like terms: 0 + 42 = 42
63m = 42
Divide each side by '63'.
m = 0.6666666667
Simplifying
m = 0.6666666667=2/3 when simplified
