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Serhud [2]
3 years ago
5

Identify the function shown in this graph.

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
6 0
A is the correct answer because the y-intercept is -2 and the slope is 3 because it goes up 3 units.
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Clarissa went to her favorite restaurant for dinner. if her meal cost 12.00 and she wants to add a 15 %tip how much is her total
Natalija [7]
12.00*0.15=1.80
12+1.80=13.80
Total bill = $13.80
3 0
4 years ago
Read 2 more answers
The probability of flu symptoms for a person not receiving any treatment is 0.038. In a clinical trial of a common drug used to
alexgriva [62]

Answer:

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 1164, p = 0.038

So

\mu = E(X) = np = 1164*0.038 = 44.232

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = 6.5231

Estimate the probability that at least 47 people experience flu symptoms.

Using continuity correction, this is P(X \geq 47 - 0.5) = P(X \geq 46.5), which is 1 subtracted by the pvalue of Z when X = 46.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.5 - 44.232}{6.5231}

Z = 0.35

Z = 0.35 has a 0.6368

1 - 0.6368 = 0.3632

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

6 0
3 years ago
Plz help thankssssssssssssssss
Kisachek [45]

what do you need help with

5 0
4 years ago
Help with number 6 pleaseeeeeeee
vitfil [10]
SinA=5root3/10
CosA=5/10
TanA=5root3/5=root3
SinC=5/10=1/2=0.5
CosC=5root3/10
Tanc=5/5root3=1/root3
7 0
3 years ago
What are theutilities
Leno4ka [110]

Hope it helps yah (◕ᴗ◕✿)

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