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Bingel [31]
3 years ago
9

who spends 2/3 of his money on a video game before spending half of his remaining money on lunch if his lunch cost $10 how much

money did he have at first
Mathematics
2 answers:
romanna [79]3 years ago
7 0

2/3 on video games

1/3 left

1/3 x 1/2 = 10 (half of 1/3 is $10)

= 1/6 of the whole

1/6 x 10 = 60

Therefore, you have $60 at first


finlep [7]3 years ago
3 0

We have to work backwards for this. Since his lunch came at $10 and it says half of his remaining money, this means that $10 was half and the real value was $20. Now since he spent 2/3 of his money on video games, this means that $20 is only 1/3 of that, so we multiply by 3 and we get the original amount of $60.

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A number divided by sixsix is 270. what is the number
9966 [12]
The answer is 1,620

1,620/6= 270
3 0
3 years ago
A nationwide sample of influential Republicans and Democrats was asked as a part of a comprehensive survey whether they favored
pickupchik [31]

Answer:

We conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.

Step-by-step explanation:

<u>The complete question is</u>: A nationwide sample of influential Republicans and Democrats was asked as a part of a comprehensive survey whether they favored lowering environmental standards so that high-sulfur coal could be burned in coal-fired power plants. The results were:

Number sampled: 1,000 (republican) , 800 (democrats)

Number in favor: 200 (republican) , 168 (democrats)

At the 0.02 level of significance, can we conclude that there is a larger proportion of Democrats in favor of lowering the standards? Determine the p-value.

Let p_1 = <u><em>proportion of Republicans in favor of lowering the standards</em></u>.

p_2 = <u><em>proportion of Democrats in favor of lowering the standards</em></u>.

SO, Null Hypothesis, H_0 : p_1 \geq p_2     {means that there is an equal or larger proportion of Republicans in favor of lowering the standards}

Alternate Hypothesis, H_A : p_1 < p_2     {means that there is a larger proportion of Democrats in favor of lowering the standards}

The test statistics that would be used here <u>Two-sample z-test for</u> <u>proportions</u>;

                         T.S. =  \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }  ~ N(0,1)

where, \hat p_1 = sample proportion of Republicans in favor of lowering the standards = \frac{200}{1000} = 0.20

\hat p_2 = sample proportion of Democrats in favor of lowering the standards = \frac{168}{800} = 0.21

n_1 = sample of Republicans = 1000

n_2 = sample of Democrats = 800

So, <u><em>the test statistics</em></u>  =  \frac{(0.20-0.21)-(0)}{\sqrt{\frac{0.20(1-0.20)}{1000}+\frac{0.21(1-0.21)}{800} } }

                                     =  -0.52

The value of z test statistics is -0.52.

<u>Now, P-value of the test statistics is given by the following formula; </u>

            P-value = P(Z < -0.52) = 1 - P(Z \leq 0.52)

                          = 1 - 0.6985 = 0.3015

Now, at 0.02 significance level, the z table gives a critical value of -2.054 for left-tailed test.

Since our test statistic is more than the critical value of z as -0.52 > -2.054, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <em><u>we fail to reject our null hypothesis</u></em>.

Therefore, we conclude that there is an equal or larger proportion of Republicans in favor of lowering the standards.

7 0
3 years ago
Bag of candy contains 4 strawberry
Andreas93 [3]

There are 9 candies in total, with 5 being orange. Think of it. For the first grab, you have a 5/9 chance of it being orange flavored. Now there are 4 orange flavored candies, and 8 total candies in the bag. Grabbing a second candy, Billy has a 4/8 chance of grabbing an orange flavored candy. So your two fractions are...

5/9, 4/8

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Tcecarenko [31]
I hope this helps you


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ziro4ka [17]
The correct answer is
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