What is the product of 5/12 and 1/3

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n 2 if heads comes up

Artyom0805 [142]

Answer:

In the long run, ou expect to lose $4 per game

Step-by-step explanation:

Suppose we play the following game based on tosses of a fair coin. You pay me $10, and I agree to pay you $n^2 if heads comes up first on the nth toss.

Assuming X be the toss on which the first head appears.

then the geometric distribution of X is:

X $\sim$ geom(p = 1/2)

the probability function P can be computed as:

$P (X = n) = p(1-p)^{n-1}$

where

n = 1,2,3 ...

If I agree to pay you $n^2 if heads comes up first on the nth toss.

this implies that , you need to be paid $\sum \limits ^{n}_{i=1} n^2 P(X=n)$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = E(X^2)$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =Var (X) + [E(X)]^2$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+(\dfrac{1}{p})^2$ ∵ X $\sim$ geom(p = 1/2)

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p}{p^2}+\dfrac{1}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{1-p+1}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-p}{p^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) = \dfrac{2-\dfrac{1}{2}}{(\dfrac{1}{2})^2}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{4-1}{2} }{{\dfrac{1}{4}}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ \dfrac{3}{2} }{{\dfrac{1}{4}}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =\dfrac{ 1.5}{{0.25}}$

$\sum \limits ^{n}_{i=1} n^2 P(X=n) =6$

Given that during the game play, You pay me $10 , the calculated expected loss = $10 - $6

= $4

∴

In the long run, you expect to lose $4 per game

3 0

3 years ago

2) Multiply<br> (6x+3)(3x2+8x+5)<br> Help, please shore me how to do this!

Brrunno [24]

Answer:

Result :

3 • (2x + 1) • (x + 1) • (3x + 5)

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

STEP1

Equation at the end of step 1

(6x + 3) • ((3x2 + 8x) + 5)

STEP2

STEP3

Pulling out like terms

3.1 Pull out like factors :

6x + 3 = 3 • (2x + 1)

Trying to factor by splitting the middle term

3.2 Factoring 3x2 + 8x + 5

The first term is, 3x2 its coefficient is 3 .

The middle term is, +8x its coefficient is 8 .

The last term, "the constant", is +5

Step-1 : Multiply the coefficient of the first term by the constant 3 • 5 = 15

Step-2 : Find two factors of 15 whose sum equals the coefficient of the middle term, which is 8 .

-15 + -1 = -16

-5 + -3 = -8

-3 + -5 = -8

-1 + -15 = -16

1 + 15 = 16

3 + 5 = 8 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 3 and 5

3x2 + 3x + 5x + 5

Step-4 : Add up the first 2 terms, pulling out like factors :

3x • (x+1)

Add up the last 2 terms, pulling out common factors :

5 • (x+1)

Step-5 : Add up the four terms of step 4 :

(3x+5) • (x+1)

Which is the desired factorization

sorry if its too much...

7 0

3 years ago

N/4 + 12 =18 i will give brainllest

Hoochie [10]

Answer:

n = 24

Step-by-step explanation:

subtract 12

n/4 = 6

multiply by 4

n = 24

7 0

2 years ago

Read 2 more answers

On a coordinate plane, a line goes through (negative 3, 2) and (0, 1). A point is at (3, 4). What is the equation of the line th

Novay_Z [31]

Answer:

$y=3x-5$

Step-by-step explanation:

step 1

Find the slope of the given line

we have

(-3,2) and (0,1)

The slope m is

$m=(1-2)/(0+3)=-1/3$

step 2

Find the slope of the line perpendicular to the given line

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of its slopes is -1)

so

The slope is

$m=3$

step 3

Find the equation of the line in point slope form

we have

$m=3$

$point(3,4)$

$y-4=3(x-3)$ ----> equation in point slope form

Convert to slope intercept form

$y=3x-9+4$

$y=3x-5$

6 0

3 years ago

Read 2 more answers

How can you find the area of an irregular polygon using area formulas?

algol [13]

Divide the polygon into separate shapes. Like a rectangle and then a triangle.
find the areas of those shapes and then add them together.

6 0

3 years ago