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algol13
3 years ago
12

Find the simple interest and the total amount after three years.

Mathematics
1 answer:
ZanzabumX [31]3 years ago
5 0

Answer:

\boxed{ \sf{Total \:Interest =  \underline{ 2223} \: rupees}}

\boxed{ \sf{Total \: Amount =  \underline{10023} \: rupees}}

Step-by-step explanation:

<h3>♨ Given :</h3>
  • Principal ( P ) = 7800 rupees
  • Annual rate of interest ( R ) = 9.5 %
  • Time ( T ) = 3 years

<h3>♨ To find :</h3>
  • Total interest ( I ) = ?
  • Total amount ( A ) = ?

<h3>✎ Finding the total interest :</h3>

\boxed{ \sf{Simple \: interest  \: ( \:  I\: )\:  =   \frac{Principal \: ( \: P \: ) \:  \times  \: Time \: ( \: T \: ) \:  \times  \: Rate \: ( \: R \: )}{100}}}

\longrightarrow{ \sf{ \frac{7800 \times 3 \times 9.5}{100}}}

\longrightarrow{ \sf{ \frac{222300}{100}}}

\longrightarrow{ \sf{2223 \: rupees}}

The total interest = <u>2</u><u>2</u><u>2</u><u>3</u> rupees.

<h3>✎ Finding the total Amount :</h3>

\boxed{ \sf{Amount \: (A) = Principal \: ( \: P \: ) \:  +  \: Interest \: ( \: I \: )}}

\longrightarrow{ \sf{7800 \: rupees + 2223 \: rupees}}

\longrightarrow{ \sf{10023 \: rupees}}

The total amount = <u>1002</u><u>3</u> rupees.

--------------------------------------------------------------

<h3>☞ Additional Info :</h3>
  • Principal : The money which is borrowed or deposited is called principal ( P ).
  • Interest : The additional amount of money which is paid by borrower to the lender is called Interest ( I ) .
  • Time : The duration of time for which principal is deposited or borrowed is termed as time period ( T ).
  • Rate : The condition under which the interest is charged is called rate ( R ).
  • Amount : The sum of principal and interest is called an amount ( A ).

<h3>✑ Important Formulaes :</h3>
  • \sf{Interest \:  =  \frac{Principal \times Time \times Rate}{100}}

  • \sf{Principal =  \frac{Interest \:  \times  \: 100}{Time \times Rate}}

  • \sf{Time =  \frac{Interest \:  \times  \: 100}{Principal \times Rate}}

  • \sf{Rate =  \frac{Interest \:  \times  \: 100}{Principal \times Time}}

  • \sf{Amount = Principal + Interest}

  • \sf{Principal = Amount - Interest}

  • \sf{Interest = Amount - Principal}

Hope I helped!

Have a wonderful time ツ

~TheAnimeGirl

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Answer:

  1. 30m +50 = 20m +100
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Step-by-step explanation:

1. The expression for c in the first equation is (30m+50). Substituting that for c in the equation ...

  c = 20m +100

gives you ...

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3 years ago
ABCD is a parallelogram. What is the measure of ∠ACD?
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or, x= 162/18

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or, <ACD = 7x-3

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The answer for :

h. \:  \:   \: \frac{5}{6}

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k. \:  \:  \:  \frac{-29}{20}

l. \:  \:  \:  \frac{13}{15}

Step-by-step explanation:

Question h:

\frac{2}{3}  + ( \frac{1}{3}  \times  \frac{1}{2} )

=  \frac{2}{3}  +  \frac{1}{6}

=  \frac{2 \times 2}{3 \times 2}  +  \frac{1}{6}

=  \frac{4}{6}  +  \frac{1}{6}

=  \frac{5}{6}

Question i:

\frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3}{2}  -  \frac{5}{8} )

=  \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3 \times 4}{2 \times 4}  -  \frac{5}{8} )

= \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{12}{8}  -  \frac{5}{8} )

=  \frac{7}{8}  +  (\frac{1}{4}  \times  \frac{7}{8} )

=  \frac{7}{8}  +  \frac{7}{32}

=  \frac{7  \times 4}{8 \times 4}  +  \frac{7}{32}

=  \frac{28}{32}  +  \frac{7}{32}

=  \frac{35}{32}

Question k:

\frac{3}{4}  - ( \frac{12}{7}  \div  \frac{12}{21} ) +  \frac{4}{5}

=  \frac{3}{4}  - ( \frac{12}{7}  \times  \frac{21}{12} ) +  \frac{4}{5}

=  \frac{3}{4}  -  \frac{3}{1}  +  \frac{4}{5}

= \frac{3 \times 5}{4 \times 5}  -  \frac{3 \times 20}{1 \times 20} +  \frac{4 \times 4}{5 \times 4}

=  \frac{15}{20}   -   \frac{60}{20} +  \frac{16}{20}

=  -  \frac{29}{20}

Question l:

\frac{5}{2}  \times ( \frac{2}{3}  -  \frac{1}{5} ) - ( \frac{2}{5}  \div  \frac{4}{3} )

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=  \frac{5}{2}  \times ( \frac{10}{15}  -  \frac{3}{15} ) -  \frac{3}{10}

=  (\frac{5}{2} \times   \frac{7}{15}) -  \frac{3}{10}

=  \frac{7}{6}  -  \frac{3}{10}

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=  \frac{35}{30}  -  \frac{9}{30}

=  \frac{26}{30}

=  \frac{13}{15}

8 0
3 years ago
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