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creativ13 [48]
3 years ago
10

What's the domain of this function graph? A) (-♾, 0) B) (0,♾) C) (-♾,♾) D) (1,♾)

Mathematics
2 answers:
Yuri [45]3 years ago
8 0
B because infinity I think
Scilla [17]3 years ago
4 0

Answer:

b) (0,infinity)

Step-by-step explanation:

You can look at the graph and see it starts when x=1, and continues forever in the positive direction.

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yuradex [85]

Answer:

B) 2 1/4

Step-by-step explanation:

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3 years ago
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Alex_Xolod [135]
Its the third option y-9=-1/4(x+2) because the equation for point slope form is y-y1= m(x-x1) so because there is a negative 2 it is a positive 2. Remember a negative minus a negative is a positive. Hope this helped :)!
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3 years ago
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The graph of the parent function f(x) = x3 is translated such that the resulting graph can be represented by the function g(x) =
kirill115 [55]

Answer:

Translated 1 to the right and up one

Step-by-step explanation:

When the number is inside the parenthesis with x, that value represents a horizontal shift. because the original equation is (x-h), the opposite sign of the x value must be taken. so in this case the x value would be +1 because that is the opposite of -1, which means the function is being moved one to the right. when the number is being added to the outiside of the parenthesis, then you take that value for the vertical translations of the graph. because the original equation is (x-h)+k, then in this case there would be a vertical shift up by 1

8 0
3 years ago
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Identify the slope by converting standard form into slope-intercept form.<br> 12x - 9y = -9
Novosadov [1.4K]

Answer:

4/3

Step-by-step explanation:

12x-9y=-9

9y=12x-(-9)

9y=12x+9

y=12/9x+9/9

y=4/3x+1

y=mx+b where m=slope and b=y-intercept,

so the slope is 4/3

8 0
3 years ago
What is a cubic polynomial function with zeros 3,3 and -3? show your work.​
Brums [2.3K]

Answer:

Cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

Step-by-step explanation:

We need to find a cubic polynomial function with zeros 3,3 and -3.

If zeros of polynomial are: 3,3,and -3

we can write:

x=3, x=3, x=-3

Or

We can write:

x-3=0, x-3=0, x+3=0

Now, we can write them as:

(x-3)(x-3)(x+3)=0

Multiplying the terms, we can find the polynomial:

(x-3)(x-3)(x+3)=0\\(x(x-3)-3(x-3))(x+3)=0\\(x^2-3x-3x+9)(x+3)=0\\(x^2-6x+9)(x+3)=0\\x(x^2-6x+9)+3(x^2-6x+9)=0\\x^3-6x^2+9x+3x^2-18x+27=0\\x^3-6x^2+3x^2+9x-18x+27=0\\x^3-3x^2-9x+27=0

So, cubic polynomial function with zeros 3,3 and -3 is \mathbf{x^3-3x^2-9x+27=0}

4 0
3 years ago
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