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Mama L [17]
3 years ago
12

PLEASE HELP ME ITS MULTIPLE CHOICE

Mathematics
1 answer:
Olenka [21]3 years ago
5 0

Answer:

Step-by-step explanation:

The answer is class D so number 4

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If your struggling with math but can’t talk to a teacher parent or guardian what is the best thing to do.?
arlik [135]
There are a number of things you can try.
1. Why can't you talk to your teacher? That's always possible or it should be.
2. You can find someone else whom you know that can do math. Attach yourself to them until you can do your math alone.
3. Come here. Answer questions that you can do. Build up your points so that you can ask questions. Ask them. When you find someone on here that consistently knows what they are doing, make contact with them.
4. Offer just slightly more than 5 + 3 points. like maybe 7 and 4
5. Don't cheat. Put up questions that you need explanations for that are homework questions. The mods here are pretty strict, and they are quick to jump on to things that they can prove are cheating.
4 0
4 years ago
Expand - 4x(x^2 - y)​
vivado [14]

Answer:

-4x³ + 4xy

Step-by-step explanation:

distribute -4x by 'x²' and '-y'

-4x(x²) = -4x³

-4x(-y) = 4xy

7 0
3 years ago
Read 2 more answers
Roberto read 42 books over 7 month. He read the same number of books each month. How many books did Roberto read each month.
Sever21 [200]
Roberto read 6 books a month.
4 0
3 years ago
Plzzzzzz helpppppp!!!!!!
stepladder [879]

Answer:

h(x) ≤ 5

Step-by-step explanation:

The function and boundaries given are;

h(x) = x + 2, x < 3

And ;

h(x) = -x + 8, x ≥ 3

Now,in the first condition, the maximum value of x will be 2. This means the maximum value of h(x) there is;

h(2) = 2 + 2 = 4

For the second condition, x ≥ 3. Thus, the maximum value of x is 3.

This means that the maximum value of h(x) here is;

h(3) = -3 + 8 = 5

Foe the 2 conditions combined it is clear that the maximum value of h(x) is 5.

Thus,we can say; h(x) ≤ 5

3 0
3 years ago
Help please thank you
lara31 [8.8K]

One of the rules of logarithms is as follows;

\begin{gathered} \log _ab=x \\ Is\text{ equivalent to,} \\ a^x=b \end{gathered}

We can now insert the corresponding values in the question provided, as shown below;

\begin{gathered} \log _2\frac{1}{16}=-4 \\ \text{This is equivalent to,} \\ 2^{-4}=\frac{1}{16} \end{gathered}

Note that, one of the rules of exponents, states that a number when raised to the power of a negative value, is equivalent to the reciprocal of that expression. An example is shown below;

a^{-x}=\frac{1}{a^x}

Therefore, our equation can now be re-written as follows;

\begin{gathered} 2^{-4}=\frac{1}{16} \\ \frac{1}{2^4}=\frac{1}{16}^{} \\ \frac{1}{16}=\frac{1}{16} \end{gathered}

However, the question requires the answer to be expressed in exponential form. Therefore,

\log _2\frac{1}{16}=2^{-4}

4 0
2 years ago
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