If uw = 6x - 35, find uw

The volume of a cylinder can be expressed as V=πr2h, where r is the radius, and h is the height of the cylinder.

olga_2 [115]

<em>Note: You missed to add the answer choices, so I am solving the overall procedure to determine the radius of the cylinder so that you could easily figure out the right choice.</em>

Answer:

The radius of the cylinder:

$r\:=\:\sqrt{\frac{v}{\pi \:h}}$

Step-by-step explanation:

The volume of a cylinder is represented by the formula

V=πr²h

here

r is the radius

h is the height

The radius of the cylinder can be computed using the formula of the volume of a cylinder

V = πr²h

r² = V / πh

Taking square roots

$r\:=\:\sqrt{\frac{v}{\pi \:h}}$

Thus, the formula of the radius of the cylinder.

$r\:=\:\sqrt{\frac{v}{\pi \:h}}$

Therefore, the radius of the cylinder:

$r\:=\:\sqrt{\frac{v}{\pi \:h}}$

7 0

3 years ago

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites. Assume you obtain a r

kicyunya [14]

Answer:

a) 0.2316 = 23.16% probability that 0 carry intestinal parasites.

b) 0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

Step-by-step explanation:

For each trout, there are only two possible outcomes. Either they carry intestinal parasites, or they do not. Trouts are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

You know that in a specific population of rainbow trout 15% of the individuals carry intestinal parasites.

This means that $p = 0.15$

Assume you obtain a random sample of 9 individuals from this population:

This means that $n = 9$

a. Calculate the probability that __ (last digit of your ID number) carry intestinal parasites.

Last digit is 0, so:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316$

0.2316 = 23.16% probability that 0 carry intestinal parasites.

b. Calculate the probability that at least two individuals carry intestinal parasites.

This is

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{9,0}.(0.15)^{0}.(0.85)^{9} = 0.2316$

$P(X = 1) = C_{9,1}.(0.15)^{1}.(0.85)^{8} = 0.3679$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2316 + 0.3679 = 0.5995$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5995 = 0.4005$

0.4005 = 40.05% probability that at least two individuals carry intestinal parasites.

5 0

3 years ago

Pls help me it is urgent

Anna007 [38]

Answer: C

Step-by-step explanation:

The area of a rectangle is just the length multiplied by its height. The length of this rectangle is (x+5), while the height is just 3. Therefore the answer is:

$3(x+5)$

4 0

2 years ago

A letter is chosen from the word ROCK and a standard die is

gavmur [86]

Answer:

ummm well to change your UN you have to email the brainly FAQ and ask if you can im trying to change myne to

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which is the graph of f(x) = 5(2)x?

dmitriy555 [2]

Step-by-step explanation:

Find the y value at y=0

Replace the variable x with 0

in the expression.

f ( 0 ) = 5⋅ 2 0

Simplify the result.

5

The y value at x = 0 is 5 . y = 5

Find the

y value at x = − 1

y = 5 2

Find the

y

value at

x

=

−

2

.

y

=

5

4

Find the

y

value at

x

=

1

.

y

=

10

Find the

y

value at

x

=

2

.

Tap for more steps...

y

=

20

List the points to graph.

(

0

,

5

)

,

(

−

1

,

2.5

)

,

(

−

2

,

1.25

)

,

(

1

,

10

)

,

(

2

,

20

)

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is

y

=

0

.

Horizontal Asymptote:

y

=

0

Use the found points and asymptotes to graph

y

=

5

⋅

2

x

.

Horizontal Asymptote:

y

=

0

x

y

−

2

1.25

−

1

2.5

0

5

1

10

2

20

Find the

y

value at

x

=

−

1

.

Tap for more steps...

y

=

5

2

Find the

y

value at

x

=

−

2

.

Tap for more steps...

y

=

5

4

Find the

y

value at

x

=

1

.

y

=

10

Find the

y

value at

x

=

2

.

y

=

20

List the points to graph.

(

0

,

5

)

,

(

−

1

,

2.5

)

,

(

−

2

,

1.25

)

,

(

1

,

10

)

,

(

2

,

20

)

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is

y

=

0

.

Horizontal Asymptote:

y

=

0

Use the found points and asymptotes to graph

y

=

5

⋅

2

x

.

Horizontal Asymptote:

y

=

0

x

y

−

2

1.25

−

1

2.5

0

5

1

10

2

20

Find the

y

value at

x

=

−

1

.

Tap for more steps...

y

=

5

2

Find the

y

value at

x

=

−

2

.

Tap for more steps...

y

=

5

4

Find the

y

value at

x

=

1

.

Tap for more steps...

y

=

10

Find the

y

value at

x

=

2

.

Tap for more steps...

y

=

20

List the points to graph.

(

0

,

5

)

,

(

−

1

,

2.5

)

,

(

−

2

,

1.25

)

,

(

1

,

10

)

,

(

2

,

20

)

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is

y

=

0

.

Horizontal Asymptote:

y

=

0

Use the found points and asymptotes to graph

y

=

5

⋅

2

x

.

Horizontal Asymptote:

y

=

0

x

y

−

2

1.25

−

1

2.5

0

5

1

10

2

20

Find the

y

value at

x

=

−

1

.

Tap for more steps...

y

=

5

2

Find the

y

value at

x

=

−

2

.

y

=

5

4

Find the

y

value at

x

=

1

.

y

=

10

Find the

y

value at

x

=

2

.

y

=

20

List the points to graph.

(

0

,

5

)

,

(

−

1

,

2.5

)

,

(

−

2

,

1.25

)

,

(

1

,

10

)

,

(

2

,

20

)

Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is

y

=

0

.

Horizontal Asymptote:

y

=

0

Use the found points and asymptotes to graph

y

=

5

⋅

2

x

.

Horizontal Asymptote:

y

=

0

x

y

−

2

1.25

−

1

2.5

0

5

1

10

2

20

6 0

4 years ago

If uw = 6x - 35, find uw​

If uw = 6x - 35, find uw