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3 years ago

The Factor Theorem states:

Mathematics

1 answer:

Hoochie [10]3 years ago

8 0

Ur ans will be bit 3
if x-k is a factor then f(k)=0

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Carl is boarding a plane. He has 2 checked bags of equal weight and a backpack that weighs 4 kg. The total weight of Carl's bagg

aniked [119]

<span>Carl has 3 bags in total. One backpack weighs 4 kg and the rest two checking bags have the equal weight. The total weight of 3 bags is given to be 35 kg.

Let the weight of each checking bag is w kg. So we can write:

2 x (Weight of a checking bag) + Weight of Backpack = 35

Using the values, we get:

2w+ 4 = 35

Using this equation we can find the weight of each checking bag, as shown below.

2w = 31

w = 31/2

w = 15.5

Thus, the weight of each checking bag is 15.5 kg
</span>

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4 years ago

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The following set of coordinates represent which figure?(7,10) (4,7) (6,5) (9,8)

Crank

Answer: i think a diamond

Step-by-step explanation:

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3 years ago

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Find the function f (x) =ax2 + bx+ c whose graph contains the points (1, 2), (-2,-7), and (2, -3). Write the system of equations

yan [13]

what grade you r?????....

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3 years ago

How to solve 2x^2 - 4x = 3

zhenek [66]

Answer:

1 ± i(1/2)√2

Step-by-step explanation:

Write this quadratic in standard form: subtract 3 from both sides. This results in 2x^2 - 4x - 3 = 0. Let's apply the quadratic formula. The coefficients of the x terms are 2, -4 and -3, so the discriminant is (-4)^2 - 4(2)(-3), or 16 - 24 = -8.

Following the format of the quadratic formula, we get

-(-4) ±i2√8 4 ±i2√2

x = ----------------- = --------------- = 1 ± i(1/2)√2

4 4

6 0

3 years ago

Use the function f(x) = 4x2 − 7x − 15 to answer the questions. Part A: Completely factor f(x). (2 points) Part B: What are the x

makkiz [27]

Answer:

Part A: f(x) = 4·x² - 7·x-15 = (x - 3)·(4·x + 5)

Part B: The x-intercepts are x = 3 and -1.25 #

Part C: As x approaches ∞, y approaches ∞, as x approaches -∞, y approaches ∞

Part D: The graph is a u-shaped quadratic equation graph passing though the x-intercept points -1.25 and 3 on the x-axis and the y-intercept point -15 on the y-axis. Both sides of the symmetrical graph curve extending to infinity

Step-by-step explanation:

The function 4·x² - 7·x-15

To factorize the expression, we have at the 0 factors;

$x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a}$

Where;

a = 4, b = -7, c -15, substituting gives;

$x = \dfrac{-(-7)\pm \sqrt{(-7)^{2}-4\times 4\times (-15)}}{2\times 4} = \dfrac{7\pm 17}{8} = 3 \ or -1.25$

Which gives;

(x - 3)·(x + 1.25) = (x - 3)·(4·x + 5)

f(x) = 4·x² - 7·x-15 = (x - 3)·(4·x + 5)

Part B: The x-intercepts are the point where y = 0, which are x = 3 and -1.25 as shown above

Part C: As x approaches ∞, y approaches ∞, as x approaches -∞, y approaches ∞

Part D: With the the nature of the function as y approaches ∞ and -∞ the graph is a u-shaped graph of a quadratic equation passing though the points -1.25 and 3 on the x-axis and the point -15 on the y-axis.

6 0

3 years ago