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zhannawk [14.2K]

2 years ago

14

The cost of renting a boat is $51 for 5 hours. Which of the following is not an equivalent rate? Give the letter of your answer

and justify your answer. Show your work.
A. $61.20 for 6 hours

B. $30.60 for 3 hours

C. $71.40 for 7 hours

D. $41.20 for 4 hours

1 answer:

alexgriva [62]2 years ago

4 0

B. Obviously all the numbers have to do with one and it’s 30. If it’s wrong let me know !

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Please show your work!!!!

viva [34]

Answer:

4√34

Step-by-step explanation:

Let the unknown side be y

y^2 = 20^2 + 12^2

y^2 = 400 + 144

y^2 = 544

Take the square root of both side

y = √544

y = √(16x34)

y = √16 x √34

y = 4√34

6 0

3 years ago

A dog and a cat start running from the same corner

Shalnov [3]

Answer:

whats the question?

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

If 5(x + 7)= -3, then 5x +35= -3

tensa zangetsu [6.8K]

= 5x + 35 = -3
- 35 = -35
5x = -38
/ 5 = / 5
x = -7.6

8 0

3 years ago

sdas [7]

Answer:

88/7 ft = 12.6 ft (nearest tenth)

Step-by-step explanation:

Circumference of a circle = 2 $\pi$ r

<u>Radius of inner circle</u>

Given:

circumference of inner circle = 22ft
$\pi$ = 22/7

⇒ 22 = 2 x (22/7) x r

⇒ r = 3.5

So the radius of the inner circle is 3.5 ft

<u>Radius of outer circle</u>

If the distance between the inner circle and the outer circle is 2 ft, then the radius of the outer circle = 3.5 + 2 = 5.5

<u>Circumference of outer circle</u>

Therefore, circumference of outer circle:

= 2 x (22/7) x 5.5

= 242/7 ft

<u>Difference between circumferences</u>

Difference = outer circle circumference - inner circle circumference

= 242/7 - 22

= 88/7 ft

= 12.6 ft (nearest tenth)

4 0

2 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

So

$P(x \ge 60) \approx P(z > 1.34)$

$= 1-P(z \le 1.34)$

$=1-0.9099$

$=0.0901$

3 0

3 years ago